A particle moving along the xx-axis has its position described by the function x=(5t4+6t2+2t+5)m, where t is in s.At t = 12 s, what is the particle's position?
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Q: A particle moving along the xx-axis has its position described by the function x=(4t3+5t+2)m, where…
A: Given : x=(4t3+5t+2)m
Q: A particle moving along the xx-axis has its position described by the function…
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- A particle moving along the xx-axis has its position described by the function x=(4t3+5t+2)mx=(4t3+5t+2)m, where t is in s. At t = 2 s, what is the particle's position?A particle performs a one-dimensional motion with the position given by the time equation x(t) = 1,3t4 - 2,0t3, where x is given in meters and t is given in seconds. At time t=0, the particle starts its motion at the origin x=0. At what instant (in seconds) does the particle reverse its direction of motion?A particle moving along the xx-axis has its position described by the function x=(4t3+5t+2)mx=(4t3+5t+2)m, where t is in s. At t = 2 s, what is the particle's velocity At t = 2 s, what is the particle's acceleration?
- At time t=0s, an object is moving to the right with a velocity v that can be modeled by the equation v=(4.2 m/s)-(1.4 m/s2)t. At what time, if any, does the object change its direction of motion?A particle moves along the yy axis so that its position at any time t, for 0≤t≤5t, is given by y(t)=t4−18t2. Find the intervals in which the particle is speeding up.A spacecraft is traveling with a velocity of Vox=5950 m/s along the +x direction. Two engines are turned on for a time of 817 s. One engine give the spacecraft an acceleration in the +x direction of ax=1.18 m/s2, while the other gives it an acceleration in the +y direction of ay=7.30 m/s2. At the end of the firing, what is (a) Vx and (b) Vy?
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- An object is located at s(0)=1 and is moving along the s-axis with the velocity v(t)=4−2t. What is the total distance the particle traveled from t=0 to t=3?A particle leaves the origin with initial velocity v0= 12i + 14j m/s, undergoing constant acceleration a = -0.80i + 0.25j m/s2. If the particle crosses the y-axis at t = 30s and its y-coordinate at the time is 532.5m. How fast is it moving and in what direction is it moving?The velocity function of a particle moving along a horizontal line is given by v(t) = ln 2 * 23t , where t ≥ 0 is in seconds. The particle is initially 2/3 units to the left of the origin. Find the position of the particle when the acceleration is equal to 6(ln 2)2 .