A particle of mass m is at rest at the end of the spring (force constant k) hanging from a fixed support. At t=0, a constant downward force F is applied to the mass and acts for a time to. Show that after the force is removed, the displacement of the mass from its equilibrium position (x=xo, where x is down) is F x-x, =[cos @,(t-t,)-cos@̟t] k where w = k/m.

A particle of mass m is at rest at the end of the spring (force constant k) hanging from a fixed support. At t=0, a constant downward force F is applied to the mass and acts for a time to. Show that after the force is removed, the displacement of the mass from its equilibrium position (x=xo, where x is down) is F x-x, =[cos @,(t-t,)-cos@̟t] k where w = k/m.

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter10: Virtual Work And Potential Energy

Section: Chapter Questions

Problem 10.57P: Find the stable equilibrium position of the system described in Prob. 10.56 if m = 2.06 kg.

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