A particle P projected from a point O on horizontal ground hits the ground after 2.4 seconds. The horizontal component of the initial velocity of P is 5/3 d ms-1 The speed of P as it passes over the wall is 16ms-1 (d) Find the value of d correct to 3 significant figures.

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A particle P projected from a point O on horizontal ground hits the ground after 2.4 seconds.
The horizontal component of the initial velocity of P is 5/3 d ms-1


The speed of P as it passes over the wall is 16ms-1

(d) Find the value of d correct to 3 significant figures.

May I have the answer for D please as the rules is only to do 3 of them so I asked separately 

b Answered: A particle P projecte X
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A particle P projected from a point O on horizon...
Tw=s
S
On dividing the values,
Tw=0.6 s
y=11.76 ms-1
Step 5
On considering let height
wall is h
h = yTw + (5)g(Tw)²
Where,
g is the acceleration due to gravity
On substituting the corresponding values to the above expression,
h = (11. 76) (0. 6) + (0. 5) (–9. 8) (0. 6) (0. 6)
h = 7.056 – 1.764
h = 5. 292 m
Step 6
As per rules supposed to solve only first three subparts of the question so please post the remaining questions
as a separate one
IMG_1274.heic
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Transcribed Image Text:b Answered: A particle P projecte X + bartleby.com/questions-and-answers/a-particle-p-projected-from-a-point-o-on-horizontal-ground-hits-the-ground-after-2.4-seconds.-t... 7094 = bartleby Search for textbooks, step-by-step explanations to homework questions, Ask an Expert e Q&A Library A particle P projected from a point O on horizon... Tw=s S On dividing the values, Tw=0.6 s y=11.76 ms-1 Step 5 On considering let height wall is h h = yTw + (5)g(Tw)² Where, g is the acceleration due to gravity On substituting the corresponding values to the above expression, h = (11. 76) (0. 6) + (0. 5) (–9. 8) (0. 6) (0. 6) h = 7.056 – 1.764 h = 5. 292 m Step 6 As per rules supposed to solve only first three subparts of the question so please post the remaining questions as a separate one IMG_1274.heic 全部顯示
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