A particle with a mass of 0.500 kg is attached to a horizontal spring with a force constant of 50.0 N/m. At the moment t = 0, the particle has its maximum speed of 20.0 m/s and is moving to the left. (a) Determine the particle’s equation of motion, specifying its position as a function of time.(b) Where in the motion is the potential energy three times the kinetic energy? (c) Find the minimum time interval required for the particle to move from x = 0 to x = 1.00 m. (d) Find the length of a simple pendulum with thesame period.

Q: 1. A spring has a characteristic of k = 2.75N/m. It has an original length of 0.100 m. What is its…

A: 1 Elastic potential energy is directly proportional to the square of the change in length and the…

Q: A 0.45 kg mass sliding on a horizontal frictionless surface is attached to one end of a horizontal…

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Q: An object is attached to a horizontal spring and somewhere along its motion has a kinetic and…

A: Total mechanical energy of the system is sum of kinetic energy and potential energy. T.E = K.E…

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 5.70 ✕ 102 N/m that lies…

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Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 435 N/m as shown in the…

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Q: A scene in a movie has a stuntman falling through a floor onto a bed in the room below. The plan is…

A: Spring constant (k)= 65144 Nm Compression (d) = 14.65 cm Height of mass above the spring (h) = 4.12…

Q: How far a spring extended if it has 2.5J of elastic potential energy and its spring- constant is…

A: The formula of the elastic potential energy of a spring is  U=0.5 K x2 where, K is the spring…

Q: A block attached to a horizontal spring with a spring constant k = 200 N/m is displaced to x = +6 cm…

A: Given,  Spring constant, k = 200 N/m  Displacement = +6cm  Time needed to reach + 6cm is 0.4 s so…

Q: www A block with mass m = 5 kg is attached to two springs with spring constants kleft = 31 N/m and…

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Q: The motion of a particle connected to a horizontal spring is descrived by : x = 8sin(πt). At what…

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Q: A spring of negligible mass stretches 3.46 cm from its relaxed length when a force of 5.40 N is…

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Q: A bungee cord has a spring constant of 112 N/m. How far will it stretch if a 50.0 kg mass is hung…

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Q: MULTIPLE CHOICE A 0.50-kg block attached to aa spring of spring constant of 80N/m oscillates on a…

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Q: A 69.5 kg bungee jumper is standing on a tall platform (h0 = 53 m), as seen in the photo. The bungee…

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Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 590 N/m as shown in the…

A: Given values m = 2 kg, X = 4.05 cm = 4.05 x 10-2 m Spring constant, k=590 N/m

Q: Force Applied (N) | Extension (m) -25 N -13 N 14 N 21 N 34 N 65 N 0.250 m 0.130 m 0.140 m 0.210 m 3.…

A: Given, Force applied and extension

Q: A block of mass 1.6 kg is held against a horizontal spring so that the spring is compressed 17 cm.…

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Q: The kinetic and potential energy in function of Time for a mass attached to a spring is shown below.…

A: Potential at a given point is 12kx2 kinetic energy at that point =12kA2-x2

Q: Dv 스크린샷 2022-03-30 오후 12.0 Qv 검색 스크린샷 2022-03-30 오후 12.00.55 20.0 g object is held against the free…

A: Given that, Mass of the block (m)= 20× 10-³ kg Spring constant (k)= 25 N/m Compression (x)= 0.1 m…

Q: A 1.68 kg block is held in place against the spring by a 39 NN horizontal external force. The…

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Q: You have a simple pendulum consisting of a small 450 g mass attached to a 1.20 m long string.…

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A: Given data The mass of the block is m=2 kg The spring constant is K=180 kN/m The amplitude of the…

Q: A 0.200 kg object is attached to a horizontal spring with a spring constant of 77.0 N/m. The other…

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Q: A 0.48 kg block is attached to a spring with a spring constant 0.69 N/m. Both the spring and the…

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Q: a) Find the the work required to stretch the spring.   (b) Find the speed the block has as it…

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Q: mass attached to a spring will have a maximum kinetic energy value at the position x = ____.

A: Velocity of mass is maximum at equilibrium position.

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Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 4.30 ✕ 102 N/m that lies…

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Q: If we double the spring constant of a horizontal frictionless spring with an attached oscillating…

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Q: What stretch is necessary for the spring in this Example to have a potential energy of 5.00 J?

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Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.