A particle with mass 2.29 kg oscillates horizontally at the end of a horizontal spring. A student measures an amplitude of 0.927 m and a duration of 123 s for 72 cycles of oscillation. Find the frequency, f, the speed at the equilibrium position, Vmax, the spring constant, k, the potential energy at an endpoint, Umax, the potential energy when the particle is located 49.9% of the amplitude away from the equilibrium position, U, and the kinetic energy, K, and the speed, v, at the same position. Number f= Hz Number m/s max Number k= N/ m Number U. max J Number U= Number K= Number m/s v=

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter16: Oscillations
Section: Chapter Questions
Problem 74PQ: The total energy of a simple harmonic oscillator with amplitude 3.00 cm is 0.500 J. a. What is the...
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A particle with mass 2.29 kg oscillates horizontally at the end of a horizontal spring. A student measures an
amplitude of 0.927 m and a duration of 123 s for 72 cycles of oscillation. Find the frequency, f, the speed at
the equilibrium position, Vmax, the spring constant, k, the potential energy at an endpoint, Umax, the potential
energy when the particle is located 49.9% of the amplitude away from the equilibrium position, U, and the
kinetic energy, K, and the speed, v, at the same position.
Number
f=
Hz
Number
m/s
max
Number
k=
N/ m
Transcribed Image Text:A particle with mass 2.29 kg oscillates horizontally at the end of a horizontal spring. A student measures an amplitude of 0.927 m and a duration of 123 s for 72 cycles of oscillation. Find the frequency, f, the speed at the equilibrium position, Vmax, the spring constant, k, the potential energy at an endpoint, Umax, the potential energy when the particle is located 49.9% of the amplitude away from the equilibrium position, U, and the kinetic energy, K, and the speed, v, at the same position. Number f= Hz Number m/s max Number k= N/ m
Number
U.
max
J
Number
U=
Number
K=
Number
m/s
v=
Transcribed Image Text:Number U. max J Number U= Number K= Number m/s v=
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