A person drops a cylindrical steel bar (Y = 1.100 × 101' Pa) from a height of 4.20 m (distance between the floor and the bottom of the vertically oriented bar). The bar, of length L = 0.780 m, radius R = 0.00600 m, and mass m = 2.000 kg, hits the floor and bounces up, maintaining its vertical orientation. Assuming that the collision with the floor is elastic and that no rotation occurs, what is the maximum compression Al of the bar? Use the gravitational acceleration g = 9.81 m/s?.
A person drops a cylindrical steel bar (Y = 1.100 × 101' Pa) from a height of 4.20 m (distance between the floor and the bottom of the vertically oriented bar). The bar, of length L = 0.780 m, radius R = 0.00600 m, and mass m = 2.000 kg, hits the floor and bounces up, maintaining its vertical orientation. Assuming that the collision with the floor is elastic and that no rotation occurs, what is the maximum compression Al of the bar? Use the gravitational acceleration g = 9.81 m/s?.
Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter6: Circular Motion And Other Applications Of Newton’s Laws
Section: Chapter Questions
Problem 6.8P: Consider a conical pendulum (Fig. P6.8) with a bob of mass m = 80.0 kg on a string of length L =...
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12) A person drops a cylindrical steel bar (?=1.100×1011 Pa) from a height of 4.20 m (distance between the floor and the bottom of the vertically oriented bar). The bar, of length ?=0.780 m, radius ?=0.00600 m, and mass ?=2.000 kg, hits the floor and bounces up, maintaining its vertical orientation.
Assuming that the collision with the floor is elastic and that no rotation occurs, what is the maximum compression Δ? of the bar? Use the gravitational acceleration ?=9.81 m/s2.
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