Question

Step 1

**Sampling distribution of sample mean:**

If a random sample of size *n *is taken from a population with mean *µ* and standard deviation *σ*, then mean of all sample means is the population mean *µ* and standard deviation of all sample means is *σ*/sqrt (*n*).

Step 2

**Comparing the standard deviations:**

The population distribution has a normal shape with mean 100 (*µ* ) and standard deviation 4(*σ*). First sampling distribution considers all sample means from all possible sample of size 16(*...*

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