A Pratt truss supports three forces at joints along the bottom edge, as shown in the figure below. The forces have magnitudes F₁ = 0 kN, F₂ = 450 kN, and F3 = 100 kN. The lengths for all horizontal members is s = 9 m and for all vertical members is h = 6 m. The truss is held in equilibrium by a pin at point A and a roller at point I. Use the method of joints to determine the force in members CD, CE, DE, DF, and EF and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). B S D S F S A C E G F₁ F₂ F3 1 PCD = number (rtol=0.01, atol=1e-05) kN РСЕ = number (rtol=0.01, atol=1e-05) kN PDE = number (rtol=0.01, atol=1e-05) kN PDF = number (rtol=0.01, atol=1e-05) kN PEF= number (rtol=0.01, atol=1e-05) kN S h

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.4.14P: A crane boom of mass 450 leg with its center of mass at C is stabilized by two cables AQ and BQ (Ae=...
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A Pratt truss supports three forces at joints along the bottom edge, as shown in the figure below. The forces
have magnitudes F₁ = 0 kN, F₂ = 450 kN, and F3 = 100 kN. The lengths for all horizontal members is
s = 9 m and for all vertical members is h = 6 m. The truss is held in equilibrium by a pin at point A and a
roller at point I. Use the method of joints to determine the force in members CD, CE, DE, DF, and EF and
indicate whether they are in tension or compression.
Note: Express tension forces as positive (+) and compression forces as negative (-).
B
S
D
S
F
S
A
C
E
G
F₁
F₂
F3
1
PCD = number (rtol=0.01, atol=1e-05)
kN
РСЕ
=
number (rtol=0.01, atol=1e-05)
kN
PDE =
number (rtol=0.01, atol=1e-05)
kN
PDF =
number (rtol=0.01, atol=1e-05)
kN
PEF=
number (rtol=0.01, atol=1e-05)
kN
S
h
Transcribed Image Text:A Pratt truss supports three forces at joints along the bottom edge, as shown in the figure below. The forces have magnitudes F₁ = 0 kN, F₂ = 450 kN, and F3 = 100 kN. The lengths for all horizontal members is s = 9 m and for all vertical members is h = 6 m. The truss is held in equilibrium by a pin at point A and a roller at point I. Use the method of joints to determine the force in members CD, CE, DE, DF, and EF and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). B S D S F S A C E G F₁ F₂ F3 1 PCD = number (rtol=0.01, atol=1e-05) kN РСЕ = number (rtol=0.01, atol=1e-05) kN PDE = number (rtol=0.01, atol=1e-05) kN PDF = number (rtol=0.01, atol=1e-05) kN PEF= number (rtol=0.01, atol=1e-05) kN S h
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