A previous study gave (0.23, 0.32) as a confidence interval for p. Find the minimum sample size require to ensure that your estimate (p) will be within 0.03 of p with 99.9% confidence. IMPORTANT: Use a critical value that you found with your calculator (not from a table), and round it to 3 places after the decimal point before you plug it into a formula and perform your calculations. Do not round-off any other intermediate results. n =

Q: To determine the possible effect of a chemical treatment on the rate of seed germination, 400…

A: Givenn1=400x1=350p1^=x1n1=350400=0.8750n2=320x2=308p2^=x2n2=308320=0.9625

Q: A federal report indicated that 27% of children ages 2 to 5 years old had a good diet – an increase…

A: The provided information are: Sample proportion p^=27%=0.27 Margin of error (E) = 2% = 0.02…

Q: A random sample of 40 adults with no children under the age of 18 years results in a mean daily…

A:

Q: A random sample of 12 hollyhock plants grown from the seed in a particular packet was taken, and the…

A:

Q: A state wildlife service wants to estimate the mean number of days that each licensed hunter…

A:

Q: In a study of times required from room service at a newly opened Plaza Hotel, 20 deliveries had a…

A: Given, Mean, -x = 24.2 Standard deviation, s = 8.7 Sample size, n = 20 Degrees of freedom, df = n-1=…

Q: A wildlife study is designed to find the mean weight of salmon caught by an Alaskan fishing company.…

A: Given information Standard deviation σ= 2.10 Confidence interval = 0.95 Significance level(α) = 1-…

Q: A statistical research yields to the sample proportion of a certain feature in a certain community…

A: Givensample proportion(p^)=0.80Margin of error(E)=0.09Confidence level(α)=90%

Q: A random sample of 40 adults with no children under the age of 18 years results in a mean daily…

A: Obtain the 95% confidence interval for the mean difference in leisure time between adults with no…

Q: A random sample of 40 adults with no children under the age of 18 years results in a mean daily…

A:

Q: In a sample of n=19 lichen​ specimens, the researchers found the mean and standard deviation of the…

A: We have to find out sample size

Q: A random sample of 40 adults with no children under the age of 18 years results in a mean daily…

A: Given Data : For Sample 1 x̄1 = 5.82 n1 = 40 s1 = 2.33 For Sample 2…

Q: A group of scientists studied the adhesion of various biofilms to solid surfaces for possible use in…

A:

Q: A random sample of 50 helmets (to protect motorcyclists) was subjected to a crash test and 15…

A: Given : Sample Size, n = 50 Number of successes, x = 15 confidence level,c=0.95

Q: The heights, in inches, of orangutans are normally distributed with a population standard deviation…

A: Here, σ=3, n=17, confidence level=95% .

Q: The EPA wants to test a randomly selected sample of n water specimens and estimate the mean daily…

A: The random variable reading in water samples taken during a day follows normal distribution. The…

Q: In monitoring lead in the air after the explosion at the battery factory, it is found that the…

A: Assumptions for using t statistic:   The t statistic is used when the sample size is small…

Q: For a confidence level of 80% with a sample size of 22, find the critical t value. Round your answer…

A: Given that, 80% confidence level Sample size = 22 Degrees of freedom = 22 - 1 = 21

Q: Find the critical value zα/2 that corresponds to a 91% confidence level.

A: We have given that, Confidence interval = 91% Then,  significance level (alpha) = 0.09 If x are…

Q: To study the effect of curing temperature on shear strength of a certain rubber compound, 80…

A:

Q: A consumer magazine has conducted a simple random sample of 15 owners of a certain automobile and…

A: Obtain the 99% confidence interval for the population mean.   The 99% confidence interval for the…

Q: For a confidence level of 94% for a mean with n = 19, find the critical value t.Enter the answer to…

A: Given that, n = 19, c= 94% The degree of freedom is,

Q: An epidemiologist needs to estimate the proportion of residents of Okeechobee county that have been…

A: Given that  Margin of error =E =0.069 99% confidence.

Q: In a random sample of 250 patients, 15 experienced dizziness. A pharmaceutical company claims that…

A:

Q: A random sample of 700 units from a large consignment showed that 200 were damaged. Find (i) 95% and…

A: Given Here, A random sample of 700 units consignment showed that 200 were damaged. we want i) 95%…

Q: find the critical value t of alpha over 2 used to construct  the confidence interval for a mean from…

A: It is given that n is 5 and level of significance is 0.02.

Q: A statistical research yields to the sample proportion of a certain feature in a certain community…

A:

Q: A study is to be performed to determine a certain parameter in a community. From a previous study a…

A: We have given :  Standard deviation = 46 Sample error = 4 We have to find out n for 99% of…

Q: Past experience has indicated that the breaking strength of yarn used in manufacturing drapery…

A: Given:

Q: It was determined as a 95% confidence interval (17.55; 22.45), which was drawn in a normally…

A: It is an important part of statistics. It is widely used.

Q: A random sample of 40 adults with no children under the age of 18 years results in a mean daily…

A: Given information: Confidence interval(c)=95%. Sample size(n1)=40 Sample meanx¯1=5.67 Standard…

Q: A random sample of 40 adults with no children under the age of 18 years results in a mean daily…

A: Obtain the 95% confidence interval for the mean difference in leisure time between adults with no…

Q: Come up with  your own data for a problem that would ask for a 90% confidence interval utilizing Z.…

A:

Q: To assess the accuracy of a laboratory scale, a standard weight known to weigh 1 gram is repeatedly…

A: Solution: From the given information, confidence level is 0.95, σ=0.01 and E=0.0001.

Q: A random sample of 40 adults with no children under the age of 18 years results in a mean daily…

A:

Q: A laboratory tested twelve randomly selected chicken eggs and found that the mean amount of…

A: From the given information, n=12x¯=166.2s=5.3 Given confidence level is 90%. Significance level is…

Q: A sample of size 25 was taken from a very large population. Sample statistics, x¯ and s, were used…

A:

Q: A group of scientists studied the adhesion of various biofilms to solid surfaces for possible use in…

A: Population standard deviation is 0.66. The z-critical value for 90% confidence interval is 1.645…

Q: The owner of a small bakery has installed solar panels on the roof in the hope of reducing…

A: Obtain the 90% confidence interval estimate for the mean of reduction in electricity cost. The 90%…

Q: A random sample of size 30 from a normal population yields x̅ = 69  and s = 4.  The lower bound of a…

A:

Q: Find the critical value, t c,  used for a 97% confidence interval for the mean with a sample size of…

A: The confidence level is, 100 (1 – α) % = 97%. Hence, (1 – α) = 0.97, and the significance level is,…

Q: A random sample of 40 adults with no children under the age of 18 years results in a mean daily…

A:

Q: Suppose the scale readings are normally distributed with an unknown mean and standard deviation of…

A:

Q: The EPA wants to test a randomly selected sample of nn water specimens and estimate the mean daily…

A: It is given that margin of error (E) is 2 and the confidence level is 88.36%.

Q: Shea wants to estimate the difference between two population means and plans to use data collected…

A: We have given the following statement about the t distribution n1= 30 n2= 35 Significance level =…

Q: many water specimens are required in the sample?

A: Here use basic of confidence internet and margin of error

Q: A statistical research yields to the sample proportion of a certain feature in a certain community…

A:

Q: An electrical firm manufactures T.V. picture tubes that have a length of life that is approximately…

A: