A productionn line operattes with a mean fillling weight of 16 oz per conntainer. Over-filling or under-filling presents a serious problem and reqquires the operator to shut down the production line to readjust the filling mechanism. A quality control inspector selects a sample of 30 itemms every hour and makes the deccision of whether to shutt down the line for readjjustment at that time. Supppose that the most recent sample returns a mean of 15.82 oz and a sample standard deviation of 0.8 oz. Assume the significance level (α) is 5%. A.Formulate the null and the alternative hypotheses: Null: mu ≥ 16; Alternative: mu < 16 Null: mu = 16; Alternative: mu ≠ 16 Null: mu ≤ 15.82; Alternative: mu > 15.82 Null: mu ≤ 16; Alternative: mu > 16 Null: mu = 15.82; Alternative: mu ≠ 15.82 Null: mu ≥ 15.82; Alternative: mu < 15.82 B. What kind of test is this? (Upper-tailed, lower-tailed or two-tailed test) Two-tailed Lower-tailed Upper-tailed No answer text provided. C. Find the test statistic. Is this a z-score or a t-score?  t-score = -0.225 because population std is not given, and the sample std is given to be $0.8 z-score = -1.23 because population std is given to be $0.8 t-score = -1.23 because population std is not given, and the sample std is given to be $0.8 z-score = -0.225 because population std is given to be $0.8

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Author:Amos Gilat
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A productionn line operattes with a mean fillling weight of 16 oz per conntainer. Over-filling or under-filling presents a serious problem and reqquires the operator to shut down the production line to readjust the filling mechanism. A quality control inspector selects a sample of 30 itemms every hour and makes the deccision of whether to shutt down the line for readjjustment at that time. Supppose that the most recent sample returns a mean of 15.82 oz and a sample standard deviation of 0.8 oz. Assume the significance level (α) is 5%.

A.Formulate the null and the alternative hypotheses:

Null: mu ≥ 16; Alternative: mu < 16
Null: mu = 16; Alternative: mu ≠ 16
Null: mu ≤ 15.82; Alternative: mu > 15.82
Null: mu ≤ 16; Alternative: mu > 16
Null: mu = 15.82; Alternative: mu ≠ 15.82
Null: mu ≥ 15.82; Alternative: mu < 15.82
B. What kind of test is this? (Upper-tailed, lower-tailed or two-tailed test)

Two-tailed
Lower-tailed
Upper-tailed
No answer text provided.
C. Find the test statistic. Is this a z-score or a t-score? 

t-score = -0.225 because population std is not given, and the sample std is given to be $0.8
z-score = -1.23 because population std is given to be $0.8
t-score = -1.23 because population std is not given, and the sample std is given to be $0.8
z-score = -0.225 because population std is given to be $0.8
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