A proton accelerates in a horizontal uniform electric field of 1.4 x 105 N/C from the position of 0.01 m to 0.03 m. Calculate the change in the proton's kinetic energy. (Given the charge of proton, q = 1.60 x 1019 C) * O 4.36 x 1011 J 5.58 x 1014 J O 4.48 x 10-16 J O 5.36 x 1011 J

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Chapter25: Electric Potential
Section: Chapter Questions
Problem 25.11OQ: A proton is released from rest at the origin in a uniform electric field in the positive x direction...
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A proton accelerates in a horizontal uniform
electric field of 1.4 x 105 N/C from the
position of 0.01 m to 0.03 m. Calculate the
change in the proton's kinetic energy.
(Given the charge of proton, q = 1.60 x 1019
C) *
O 4.36 x 1011 J
O 5.58 x 1014 J
O 4.48 x 10-16 J
O 5.36 x 1011 J
Transcribed Image Text:A proton accelerates in a horizontal uniform electric field of 1.4 x 105 N/C from the position of 0.01 m to 0.03 m. Calculate the change in the proton's kinetic energy. (Given the charge of proton, q = 1.60 x 1019 C) * O 4.36 x 1011 J O 5.58 x 1014 J O 4.48 x 10-16 J O 5.36 x 1011 J
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