A random sample of n1 = 246 people who live in a city were selected and 70 identified as a "dog person." A random sample of n2 = 112 people who live in a rural area were selected and 62 identified as a "dog person." Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." %3D Round answers to to 4 decimal places.

Q: A random sample of 120 adults showed that 42 are already fully vaccinated. Give a 95% confidence…

A:

Q: In Cleveland, a random sample of 73 mail carriers showed that 10 had been bitten by an animal during…

A: Given, n1 = 73 x1 = 10 n2 = 80 x2 = 16 confidence level = 1 - α = 0.95 α = 0.05α2 = 0.025   To find,…

Q: A survey of 540 depressed shoppers found at 32% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 540 confidence level,c=0.99 Significance level, α…

Q: A large private university and a large public university selected random sample of incoming freshman…

A: Given:  p1 is the proportion of all entering freshmen at the private university who graduated in the…

Q: In a survey of 650 randomly selected U.S. males ages 18-64, 396 say they have gone to the dentist in…

A: Given,n=650x=396p^=xnp^=396650=0.6091-p^=1-0.609=0.391α=1-0.90=0.1α2=0.05Z0.05=1.645     (from…

Q: In Cleveland, a random sample of 74 mail carriers showed that 12 had been bitten by an animal during…

A:

Q: The figure to the right shows the results of a survey in which 1001 adults from Country​ A, 1002…

A: “Since you have posted a question with multiple sub-parts, we will solve the first three subparts…

Q: In a randomly selected sample of 400 registered voters in a community, 200 individuals say that they…

A: A sample of 400 registered voters in a community were randomly selected in which 200 individuals say…

Q: A simple random sample of 300 branches out of a total of 1200 branches of a UK travel agency found…

A: Given : Here population is total branches of a UK travel agency  Population Size (N) = 1200 Sample…

Q: In a random sample of 75 college students 60 of them had sunglasses.  Compute a 95% Confidence…

A: Thank you for posting the question. Since you have asked multiple question, we will solve the first…

Q: In a random sample of 500 people eating lunchbat a cafeteria on various fridays, it was found that…

A: Given X=160 n=500 P=X/n

Q: In a random sample of 500 people aged 20-24, 22% were smokers. In a random sample of 450 people aged…

A: We have to find confidence interval...

Q: A New York Times/CBS News Poll asked a random sample of U.S. adults the question “Do you favor an…

A: From the provided information, Confidence level = 95% Confidence limit = (0.63, 0.69)

Q: In a random sample of 90 homeowners, 71% of them have received robocalls over an outstanding debt.…

A: Sample size(n)=90 Sample proportion who have received robocalls  over an outstanding…

Q: Obtain a 95% confidence interval for the difference between the proportion of males and females who…

A: Given data 25% of a random sample of males plan to vote yes of a random sample of 60 32% of a random…

Q: A random sample of 75 college students of MSU is selected and 16 are found to have motorcycles on…

A: From the given information, The sample size is 75. Out of 75 students, 16 are found to have…

Q: In a random sample, 136 of 400 people given a flu vaccine experienced some discomfort. Construct a…

A: Given information n = 400 People No of people given vaccine x = 136

Q: A survey of 1,898 adults with lawns conducted by a researcher found that 45% of the adults said that…

A: Obtain the 95% confidence interval of the true proportion who said that dandelions were the toughest…

Q: Find the 68% confidence interval for the percentage of leaky diapers with a sample of 100 diapers…

A: Let X be the number of defective diapers and n is the number of diapers. From the given information,…

Q: In a random sample of 810 medical professionals, 81 prefers to work in the evening shift.  The width…

A: Given,n=810x=81p^=xnp^=81810=0.11-p^=1-0.1=0.9α=1-0.95=0.05α2=0.025Z0.025=1.96

Q: In a sample of 225 registered voters of City Unknown, 63 of 100 males and 59 of 125 females support…

A: Given  X1=63, n1=100, X2=59, n2=125

Q: A recent survey showed that among 650 randomly selected subjects who completed 4 years of college,…

A:

Q: Of 91 adults selected randomly from one town, 60 have health insurance. Find a 90% confidence…

A: From the provided information, Sample size (n) = 91 Out of which 60 have health insurance. Sample…

Q: The figure to the right shows the results of a survey in which 999 adults from Country​ A, 1006…

A: Hey, since there are multiple subparts posted, we will answer the first three subparts. If you want…

Q: In another pre-election poll, a pollster finds that 442 out of 650 people polled favor Smith.…

A: Given: Total no of people polled , n=650 No. of people favor Smith, x=442 Confidence level=95%

Q: Based on the results of a survey conducted by a group of researchers, the proportion of female…

A: Confidence interval is a process of inference which uses the sample statistics to find the range of…

Q: In a random sample of 190 people, 159 said that they watched educational television. Find the 90%…

A:

Q: A survey found that 39 of 66 people who don't drink coffee often have trouble sleeping and 44 of 88…

A: Solution: Let X1 be the number of noncoffee drinkers who have trouble sleeping, n1 be the sample…

Q: In a recent poll of 900 randomly selected adults, 37 % reported that they could not swim 24 yards…

A: Given information: In a poll of 900, randomly selected adults were examined if they could swim 24…

Q: In a sports poll, 142 of 500 randomly selected Americans indicated that they consider themselves to…

A: Given that, In a sports poll, 142 of 500 randomly selected Americans indicated that they consider…

Q: To find the proportion of San Diegans subscribed to Disney+ in 2019, a researcher randomly selected…

A: Given that, n=200 p^=101200=0.505

Q: When 328 college students are randomly selected and surveyed, it is found that 122 own a car. Find…

A: We want to find 95% CI for population proportion (p)

Q: A national opinion poll found that 44% of all American adults agree that parents should be given…

A:

Q: The figure to the right shows the results of a survey in which 997 adults from Country​ A, 1022…

A: Given data For country A n = 997

Q: In a sample of 150 men, 132 said that they had less leisure time today than they had 10 years ago.…

A: Given that, x1=132  n1=150 p1^=x1n1=132150=0.88p2^=x2n2=236250=0.944Confidence of level…

Q: Find a 99% confidence interval for the mean of weights of Siamese cats if the population standard…

A: We have given that Sample mean (x̄) = 11.8, population standard deviation (σ) = 2.1 and sample size…

Q: 4. A random sample of 64 bicycle-riding adults in Portland indicated that 24 always wore a helmet…

A:

Q: In a random sample of 200 females and 100 males who watched a certain television program, 94 females…

A: For Females : Out of 200 females , X = 94 females indicated they like it Sample proportion 1 =…

Q: In a random sample of 195 people,149 said that they watched educational television. Find the 95%…

A:

Q: n a recent Zogby International Poll, nine of 48 respondents rated the likelihood of a terrorist…

A: Given that : x = 9 n = 48

Q: A survey of 95 families showed that 40 of the families owned at least one tv. a. Find the 90%…

A: Number of families in a sample n =95 Let X be the number of families owned at least one tv = 40 p =…

Q: A poll found that82​%of a random sample of 1093 adults said that they believe in ghosts. a.…

A: a) Given that n=1093p^=82%=0.82Confidence level=99%=0.99Significance level=0.01 The z critical value…

Q: A sample of 100 shoppers chosen at random from all shoppers in a given province indicated that 55%…

A: Givan , Mean = 0.55 × 100 = 55 Standard deviation = √[(0.55)×(1-0.55)]×100 = √0.2475 × 100 = 49.749…

Q: Based on data from a survey of 1,300 randomly selected Facebook users, a 95% confidence interval for…

A: Given Information:  Sample size (n) = 1300  Confidence interval = 95%

Q: a random sample of 63, the proportion of the sample with a certain characteristic was 0.61. What is…

A:

Q: In a simple random sample of 1200 Americans age 20 and over, 138 of them were found to have Type I…

A: In a simple random sample of 1200 Americans age 20 and over, 138 of them were found to have Type I…

Q: the number of smokers in a sample of 40 students selected from university A is 14 and the number of…

A: Given data,For University An1=40x1=14p1=1440=0.35For University Bx2=84n2=380p2=84380=0.22Construct…

Q: A survey of 800 women shoppers found that 17% of them shop on impulse. what is 98% confidence…

A:

Q: A random sample of 180 men indicated that 50 were smokers, and a random sample of 150 women surveyed…

A: Given; p1=50180=0.28p2=39150=0.26Level of significance=0.02 Confidence interval is given by-…

Q: When n=343 college students are randomly selected and surveyed, it is found that x=110 own a car.…

A: Here from a sample of 343 college students 110 of them owned a car. We need a 99% CI and margin of…