A reaction is carried out by mixing together a solution of the strong acid HCl and a solution of NaOH. HC (aq) + NaОH (аq) Н,о (1) + NaCl (aq) Determine the balanced net ionic equation and enter your answer below according to the specified format.
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A: Mass of KHP = 1.372 g Volume of NaOH = 21.84 ml Density = 1.01 gml
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- A sample containing NaCl, NaBr, and inert materials weighs 1.000 g. With excess AgNO3 it gives a precipitate of AgCl and AgBr, which weighs 0.5260 g. By heating this precipitate in a current of Cl2 gas, the AgBr is converted to AgCl and the resulting precipitate then weighs 0.4260 g. What is the %NaCl and %NaBr present in the original sample?A 0.5504-g sample of KHP (potassium hydrogen phthalate, KHC8H4O4; molar mass = 204.22 g/mol) is completely dissolved in enough deionized water to make 50.00 mL of solution. The resulting solution is titrated with a NaOH solution of unknown concentration. If 21.50 mL of the base solution is needed to reach the end-point, what is the molar concentration of NaOH solution? The reaction occurs as follows: NaOH(aq) + KHC8H4O4(aq) --> NaKC8H4O4(aq) + H2O(l) (A) 0.2457 M (B) 0.1254 M (C) 0.05390 M (D) 0.03823 MThe tartaric acid, H2C4H4O6 (150.087 g/mol ) concentration in 100.0 mL wine sample was determined using 0.4050 M sodium hydroxide standard solution. In the experiment, the %w/w of tartaric acid present in the wine sample by analyzing and titrating only 25.00 mL aliquot from the 100-ml wine sample. The endpoint of titration was reached upon the addition of exactly 43.56 mL NaOH solution? (Assume the density of the wine sample is 1.000 g/mL) H2C4H4O6 + 2NaOH⟶Na2C4H4O6+2H2O What is the total (%w/w) acid content in the wine sample? 1.324 %w/w 2.648 %w/w 5.296 %w/w 10.59 %w/w
- The following reaction occurs in basic solution. Balance it by adding only OH− or H2O. (enter your answer as the sum of the coefficients) MnO4−(aq) + NO2−(aq) → MnO2(s) + NO3−(aq)A lead-acid battery uses a redox reaction in which lead(0) and lead(IV) are both converted to lead(II). This reaction is facilitated by the presence of sulfuric acid, H2SO4 , as shown by the reaction Pb+PbO2+2H2SO4→2PbSO4+2H2O Suppose that a fully charged lead-acid battery contains 1.50 L of 5.00 M H2SO4. What will be the concentration of H2SO4 in the battery after 3.40 A of current is drawn from the battery for 5.00 hours?Balance the following equations in basic solution. MnO4-(aq) + CN-(aq) --> MnO2(s) + OCN-(aq) S(s) + OCl-(aq) --> SO32-(aq) + Cl-(aq)
- The precipitation reaction between AgNO31aq2 and NaCl1aq2proceeds as follows:(a) By using data in Appendix C, calculate ΔH° for the netionic equation of this reaction. (b) What would you expectfor the value of ΔH° of the overall molecular equation comparedto that for the net ionic equation? Explain. (c) Use theresults from (a) and (b) along with data in Appendix C to determinethe value of ΔHf° for AgNO31aq2.If you complete and balance the following equation in acidicsolutionMn2+(aq) + NaBiO3(s)---->Bi3+(aq)+ MnO4-(aq) + Na+(aq)how many water molecules are there in the balanced equation(for the reaction balanced with the smallest whole-numbercoefficients)? (a) Four on the reactant side (b) Three on the product side (c) One on the reactant side (d) Seven on theproduct side (e) Two on the product sidePlease don't provide handwritten solution.... The following is a decomposition reaction. 2KCIO32KCI +302 O True O False
- Balance the following redox reactions: (a) In acidic solution, xenon trioxide reacts with iodide ion toproduce xenon gas, triiodide ion (I₃⁻), and water. (b) In basic solution, the hydrogen xenate ion (HXeO₄⁻) dispro-portionates to xenon gas, perxenate ion (XeO₆⁴⁻), water, andoxygen gas.(c) In basic solution, bismuthate ion (BiO₃⁻) reacts with man-ganese(II) ion to produce bismuth(III) and permanganate ions. (d) In basic solution, oxygen difluoride reacts to produce fluo-ride ion, oxygen gas, and water. (e) In acidic solution, manganese(IV) oxide reacts with sulfiteion to form manganese(II) ion, water, and dithionate ion(S₂O₆²⁻).(f) In one of the few reactions known for a statine, the oxidationof astinide ion by chlorine gas in acid solution produces astinateion (AtO₃⁻) and chloride ion.Choi is fond of carbonated beverages so he crafted his own soda formulation called “Sodalicious.” Ulan, who is a fellow enthusiast, also made her own formulation which she called “Soda Pop!” to challenge his friend Choi. To know which formulation is better, they sought to determine the carbonic acid content of their soda formulations using titration. In the first part of their experiment, a 0.5 Mlabeled NaOH solution was standardized against 0.350 grams of KHP (MW = 204.22 g/mol) primary standard that is 99.6% pure. The titration required 3.16 mL of the NaOH solution to reach the phenolphthalein endpoint. In the second part of their experiment, Choi and Ulan independently prepared their samples by taking 25.0-mL of their soda sample and diluting it to 30.0 mL. Using the same titrant and indicator, Choi’s “Sodalicious” required 1.39 mL of the standardized titrant to reach the endpoint, while Ulan’s “Soda Pop!” required 0.926 mL of the same titrant to reach the endpoint. A. What is the…Choi is fond of carbonated beverages so he crafted his own soda formulation called “Sodalicious.” Ulan, who is a fellow enthusiast, also made her own formulation which she called “Soda Pop!” to challenge his friend Choi. To know which formulation is better, they sought to determine the carbonic acid content of their soda formulations using titration. In the first part of their experiment, a 0.5 Mlabeled NaOH solution was standardized against 0.350 grams of KHP (MW = 204.22 g/mol) primary standard that is 99.6% pure. The titration required 3.16 mL of the NaOH solution to reach the phenolphthalein endpoint. In the second part of their experiment, Choi and Ulan independently prepared their samples by taking 25.0-mL of their soda sample and diluting it to 30.0 mL. Using the same titrant and indicator, Choi’s “Sodalicious” required 1.39 mL of the standardized titrant to reach the endpoint, while Ulan’s “Soda Pop!” required 0.926 mL of the same titrant to reach the endpoint. D. Calculate…
