A recent study found that 61 children who watched a commercial for potato chips featuring a celebrity endorser ate a mean of 36 grams of potato chips as compared to a mean of 27 grams for 51 children who watched a commercial for an alternative food snack. Suppose that the sample standard deviation for the children who watched the​ celebrity-endorsed commercial was 21.3 grams and the sample standard deviation for the children who watched the alternative food snack commercial was 12.7 grams. Complete parts​ (a) through​ (d) below.       a. Assuming that the population variances are equal and α=0.05​, is there evidence that the mean amount of potato chips eaten was significantly higher for the children who watched the​ celebrity-endorsed commercial?   Let population 1 be the weights of potato chips eaten by children who watched the​ celebrity-endorsed commercial and let population 2 be the weights of potato chips eaten by children who watched the alternative food snack commercial. What are the correct null and alternative​ hypotheses?     A. H0​: μ1−μ2≥0 H1​: μ1−μ2<0   B. H0​: μ1−μ2≠0 H1​: μ1−μ2=0   C. H0​: μ1−μ2=0 H1​: μ1−μ2≠0   D. H0​: μ1−μ2≤0 H1​: μ1−μ2>0 Your answer is correct. What is the test​ statistic?   tSTAT=2.652.65 ​(Round to two decimal places as​ needed.) What is the corresponding​ p-value?   ​p-value=0.0050.005 ​(Round to three decimal places as​ needed.) What is the correct​ conclusion?     A. Do not reject H0. There is insufficient evidence that the mean amount of potato chips eaten was significantly higher for children who watched the​ celebrity-endorsed commercial.   B. Do not reject H0. There is sufficient evidence that the mean amount of potato chips eaten was significantly higher for children who watched the​ celebrity-endorsed commercial.   C. Reject H0. There is insufficient evidence that the mean amount of potato chips eaten was significantly higher for children who watched the​ celebrity-endorsed commercial.   D. Reject H0. There is sufficient evidence that the mean amount of potato chips eaten was significantly higher for children who watched the​ celebrity-endorsed commercial. Your answer is correct. b. Assuming that the population variances are​ equal, construct a 95​% confidence interval estimate of the difference μ1−μ2 between the mean amount of potato chips eaten by the children who watched the​ celebrity-endorsed commercial and children who watched the alternative food snack commercial.   enter your response here≤μ1−μ2≤enter your response here ​(Type integers or decimals rounded to two decimal places as​ needed.)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 26PFA
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Answer B please

 

A recent study found that
61
children who watched a commercial for potato chips featuring a celebrity endorser ate a mean of
36
grams of potato chips as compared to a mean of
27
grams for
51
children who watched a commercial for an alternative food snack. Suppose that the sample standard deviation for the children who watched the​ celebrity-endorsed commercial was
21.3
grams and the sample standard deviation for the children who watched the alternative food snack commercial was
12.7
grams. Complete parts​ (a) through​ (d) below.
 
 
 
a. Assuming that the population variances are equal and
α=0.05​,
is there evidence that the mean amount of potato chips eaten was significantly higher for the children who watched the​ celebrity-endorsed commercial?
 
Let population 1 be the weights of potato chips eaten by children who watched the​ celebrity-endorsed commercial and let population 2 be the weights of potato chips eaten by children who watched the alternative food snack commercial. What are the correct null and alternative​ hypotheses?
 
 
A.
H0​:
μ1−μ2≥0
H1​:
μ1−μ2<0
 
B.
H0​:
μ1−μ2≠0
H1​:
μ1−μ2=0
 
C.
H0​:
μ1−μ2=0
H1​:
μ1−μ2≠0
 
D.
H0​:
μ1−μ2≤0
H1​:
μ1−μ2>0
Your answer is correct.
What is the test​ statistic?
 
tSTAT=2.652.65
​(Round to two decimal places as​ needed.)
What is the corresponding​ p-value?
 
​p-value=0.0050.005
​(Round to three decimal places as​ needed.)
What is the correct​ conclusion?
 
 
A.
Do not reject
H0.
There is
insufficient
evidence that the mean amount of potato chips eaten was significantly higher for children who watched the​ celebrity-endorsed commercial.
 
B.
Do not reject
H0.
There is
sufficient
evidence that the mean amount of potato chips eaten was significantly higher for children who watched the​ celebrity-endorsed commercial.
 
C.
Reject
H0.
There is
insufficient
evidence that the mean amount of potato chips eaten was significantly higher for children who watched the​ celebrity-endorsed commercial.
 
D.
Reject
H0.
There is
sufficient
evidence that the mean amount of potato chips eaten was significantly higher for children who watched the​ celebrity-endorsed commercial.
Your answer is correct.
b. Assuming that the population variances are​ equal, construct a
95​%
confidence interval estimate of the difference
μ1−μ2
between the mean amount of potato chips eaten by the children who watched the​ celebrity-endorsed commercial and children who watched the alternative food snack commercial.
 
enter your response here≤μ1−μ2≤enter your response here
​(Type integers or decimals rounded to two decimal places as​ needed.)
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