A research assistant compared brand values for three sectors in a study of 100 global brands: the financial institution sector, the technology sector, and the telecom sector. The research assistant findings are in the accompanying table. Complete parts (a) through (c) below. Click here to view the results of the study, Click here to view a partial table of critical values of the Studentized Range. Q Critical values of the Studentized Range, Q a. Complete the ANOVA summary table. Degrees of Freedom Sum of Squares Mean Source Squares F Among groups 937,740.04 2 Critical Values of the Studentized Range, Q Within groups 9,543,372.06 10,481,112.10 (Type integers or decimals rounded to two decimal places as needed.) 46 Upper 5% Polnts (a- a05) Total 48 Denominater, Numerater, df 2 34 S 6 b. At the 0.05 level of significance, is there evidence of a difference in mean brand value among the sectors? 17.97 26.98 32.82 37.08 40.41 43.12 45.40 47.36 49 2 6.09 833 5.91 9.80 10.8 11.74 12.44 13.03 885 13.54 13. Determine the hypotheses. Choose the correct answer below. 4.50 6.83 7.50 8.04 8.4 9.18 3.93 5.04 5.76 6.29 6.71 7.05 7.35 7.60 7. O A. H: Not all are equal 3.64 4.60 5.22 5.67 6.03 6.33 658 6.80 7. H;: Not all H are equal (where j= 1,2,3) OD. H H 2*s (where j= 1,2,3) 3.46 4.34 4.90 5.31 5.63 5.90 6.12 582 632 4.68 4.53 4.42 3.34 4.17 5.06 5.36 5.61 540 6.00 6. 3.26 4.04 4.9 5.17 5.02 5.24 5.60 5.77 5. 9 3.20 3.95 4.76 543 5.60 5. 10 3.15 3.11 3.08 3.88 4.33 4.66 4.91 5.12 4.82 5.00 4.75 4.95 531 5.46 5. 11 12 3.82 3.77 4.26 4.20 4.57 4.51 520 S.12 535 5.27 Determine the p-value. 13 14 3.06 3.74 3.03 3.70 4.15 4.11 4.41 4.64 4.8 4.45 4.69 4.89 5.05 5.19 513 5. 4.99 p-value = (Round to three decimal places as needed.) 15 16 3.01 3.00 3.67 3.65 4.08 4.05 4.37 4.60 4.78 4.33 4.94 508 503 evidence to conclude that there is a difference in mean brand value among the sectors. 4.56 4.74 490 Since the p-value is V than the 0.05 level of significance, V Ho. There is 4.52 4.71 17 18 2.98 2.97 2.96 3.63 3.61 3.59 4.02 4.00 3.98 4.30 4.28 4.25 486 482 4.79 4.99 5. 496 492 4.50 4.67 5. c. I the results in (b) indicate that it is appropriate, use the Tukey-Kramer procedure to determine which sectors differ in mean rating. Discuss your findings. 19 4.47 4.65 20 2.95 3.58 3.96 4.23 4.45 4.62 4.54 4.77 4.90 At the 0.05 level of significance, for which sectors is there enough evidence to conclude that the mean ratings differ? Select all that apply. 24 30 2.92 3.53 2.89 3.49 2.86 3.90 3.85 3.79 3.74 4.17 4.37 4.68 4.81 4.72 4. OA. There is a significant difference in mean brand value between technology brands and telecom brands. 4.10 4.30 4.23 4.46 460 4. 40 3.44 4.04 4.39 4.52 4.64 4. O B. There is a significant difference in mean brand value between financial institutions and technology brands. Oc. There is a significant difference in mean brand value between financial institutions and telecom brands. OD. Because there is no significant difference among the groups, the Tukey-Kramer procedure is not appropriate. 60 2.83 3.40 3.98 4.16 4.31 444 4.55 4. 120 2.80 3.36 2.77 3.31 3.69 3.63 3.92 4.24 4.10 4.03 4.17 4.36 447 00 3.86 429 4.39 DenominateE Numerater, f
A research assistant compared brand values for three sectors in a study of 100 global brands: the financial institution sector, the technology sector, and the telecom sector. The research assistant findings are in the accompanying table. Complete parts (a) through (c) below. Click here to view the results of the study, Click here to view a partial table of critical values of the Studentized Range. Q Critical values of the Studentized Range, Q a. Complete the ANOVA summary table. Degrees of Freedom Sum of Squares Mean Source Squares F Among groups 937,740.04 2 Critical Values of the Studentized Range, Q Within groups 9,543,372.06 10,481,112.10 (Type integers or decimals rounded to two decimal places as needed.) 46 Upper 5% Polnts (a- a05) Total 48 Denominater, Numerater, df 2 34 S 6 b. At the 0.05 level of significance, is there evidence of a difference in mean brand value among the sectors? 17.97 26.98 32.82 37.08 40.41 43.12 45.40 47.36 49 2 6.09 833 5.91 9.80 10.8 11.74 12.44 13.03 885 13.54 13. Determine the hypotheses. Choose the correct answer below. 4.50 6.83 7.50 8.04 8.4 9.18 3.93 5.04 5.76 6.29 6.71 7.05 7.35 7.60 7. O A. H: Not all are equal 3.64 4.60 5.22 5.67 6.03 6.33 658 6.80 7. H;: Not all H are equal (where j= 1,2,3) OD. H H 2*s (where j= 1,2,3) 3.46 4.34 4.90 5.31 5.63 5.90 6.12 582 632 4.68 4.53 4.42 3.34 4.17 5.06 5.36 5.61 540 6.00 6. 3.26 4.04 4.9 5.17 5.02 5.24 5.60 5.77 5. 9 3.20 3.95 4.76 543 5.60 5. 10 3.15 3.11 3.08 3.88 4.33 4.66 4.91 5.12 4.82 5.00 4.75 4.95 531 5.46 5. 11 12 3.82 3.77 4.26 4.20 4.57 4.51 520 S.12 535 5.27 Determine the p-value. 13 14 3.06 3.74 3.03 3.70 4.15 4.11 4.41 4.64 4.8 4.45 4.69 4.89 5.05 5.19 513 5. 4.99 p-value = (Round to three decimal places as needed.) 15 16 3.01 3.00 3.67 3.65 4.08 4.05 4.37 4.60 4.78 4.33 4.94 508 503 evidence to conclude that there is a difference in mean brand value among the sectors. 4.56 4.74 490 Since the p-value is V than the 0.05 level of significance, V Ho. There is 4.52 4.71 17 18 2.98 2.97 2.96 3.63 3.61 3.59 4.02 4.00 3.98 4.30 4.28 4.25 486 482 4.79 4.99 5. 496 492 4.50 4.67 5. c. I the results in (b) indicate that it is appropriate, use the Tukey-Kramer procedure to determine which sectors differ in mean rating. Discuss your findings. 19 4.47 4.65 20 2.95 3.58 3.96 4.23 4.45 4.62 4.54 4.77 4.90 At the 0.05 level of significance, for which sectors is there enough evidence to conclude that the mean ratings differ? Select all that apply. 24 30 2.92 3.53 2.89 3.49 2.86 3.90 3.85 3.79 3.74 4.17 4.37 4.68 4.81 4.72 4. OA. There is a significant difference in mean brand value between technology brands and telecom brands. 4.10 4.30 4.23 4.46 460 4. 40 3.44 4.04 4.39 4.52 4.64 4. O B. There is a significant difference in mean brand value between financial institutions and technology brands. Oc. There is a significant difference in mean brand value between financial institutions and telecom brands. OD. Because there is no significant difference among the groups, the Tukey-Kramer procedure is not appropriate. 60 2.83 3.40 3.98 4.16 4.31 444 4.55 4. 120 2.80 3.36 2.77 3.31 3.69 3.63 3.92 4.24 4.10 4.03 4.17 4.36 447 00 3.86 429 4.39 DenominateE Numerater, f
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 1GP
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Question
Please answer all questions, tables and data all included
| Source | Degree of Freedom | Sum of Squares | F | |
| Among Groups | 2 | 937,740.04 | ? | ? |
| Within Groups | 46 | 9,543,372.06 | ? | ? |
| Total | 48 | 10,481,112.10 |
| Group | N | Mean |
| Financial Institution | 18 | 24,494.79 |
| Technology | 18 | 59,621.64 |
| Telecom | 13 | 37,228.81 |
Transcribed Image Text:A research assistant compared brand values for three sectors in a study of 100 global brands: the financial institution sector, the technology sector, and the telecom sector. The research assistant findings are in the accompanying table. Complete parts (a) through (c) below.
Click here to view the results of the study.
Click here to view a partial table of critical values of the Studentized Range, Q.
Critical values of the Studentized Range, Q
a. Complete the ANOVA summary table.
Degrees of
Freedom
Mean
Source
Sum of Squares
Squares
F
Among groups
2
937,740.04
Criti cal Values of the Studentized Range, Q
Within groups
46
9,543,372.06
Upper 5% Points (a = 0.05)
10,481,112.10
(Type integers or decimals rounded to two decimal places as needed.)
Total
48
Denominator,
Numerator, df
df
3
4
5
6
7
10
b. At the 0.05 level of significance, is there evidence of a difference in mean brand value among the sectors?
17.97
26.98
32.82
37.08
40.41
43.12
45.40
47.36
49.07
6.09
8.33
9.80
10.88
11.74
12.44
13.03
13.54
13.99
Determine the hypotheses. Choose the correct answer below.
3
4.50
5.91
6.83
7.50
8.04
8.48
885
9.18
9.46
3.93
5.04
5.76
6.29
6.71
7.05
7.35
7.60
7.83
Hj are equal
(where j = 1,2,3)
H;: H1 = H2 = H3
B. Ho: H1 = H2 =H3
H,: Not all
A. Ho: Not all
3.64
4.60
5.22
5.67
6.03
6.33
6.58
6.80
7.00
are equal
Hj
(where j= 1,2,3)
D. Ho: H1 4 H2 # H3
H;: H1 = H2 = H3
3.46
4.34
4.90
5.31
5.63
5.90
6.12
6.32
6.49
3.34
4.17
4.68
5.06
5.36
5.61
582
6.00
6.16
3.26
4.04
4.53
4.89
5.17
5.40
5.60
5.77
5.92
O C. Ho: H1 = H2 = H3
H: H, # H2# H3
9.
3.20
3.95
4.42
4.76
5.02
5.24
5.43
5.60
5.74
10
3.15
3.88
4.33
4.65
4.91
5.12
5.31
5.46
5.60
11
3.11
3.82
4.26
4.57
4.82
5.03
5.20
5.35
5.49
Determine the p-value.
12
3.08
3.77
4.20
4.51
4.75
4.95
5.12
5.27
5.40
13
3.06
3.74
4.15
4.45
4.69
4.89
5.05
5.19
5.32
14
3.03
3.70
4.11
4.41
4.64
4.83
4.99
5.13
5.25
p-value
(Round to three decimal places as needed.)
15
3.01
3.67
4.08
4.37
4.60
4.78
4.94
5.08
5.20
16
3.00
3.65
4.05
4.33
4.56
4.74
4.90
5.03
5.15
Since the p-value is
than the 0.05 level of significance,
Ho. There is
evidence to conclude that there is a difference in mean brand value among the sectors.
17
2.98
3.63
4.02
4.30
4.52
4.71
4.86
4.99
5.11
18
2.97
3.61
4.00
4.28
4.50
4.67
4.82
4.96
5.07
c. If the results in (b) indicate that it is appropriate, use the Tukey-Kramer procedure to determine which sectors differ in mean rating. Discuss your findings.
19
2.96
3.59
3.98
4.25
4.47
4.65
4.79
4.92
5.04
20
2.95
3.58
3.96
4.23
4.45
4.62
4.77
4.90
5.01
At the 0.05 level of significance, for which sectors is there enough evidence to conclude that the mean ratings differ? Select all that apply.
24
2.92
3.53
3.90
4.17
4.37
4.54
4.68
4.81
4.92
A. There is a significant difference in mean brand value between technology brands and telecom brands.
30
2.89
3.49
3.85
4.10
4.30
4.46
4.60
4.72
4.82
40
2.86
3.44
3.79
4.04
4.23
4.39
4.52
4.64
4.74
B. There is a significant difference in mean brand value between financial institutions and technology brands.
60
2.83
3.40
3.74
3.98
4.16
4.31
4.44
4.55
4.65
120
2.80
3.36
3.69
3.92
4.10
4.24
4.36
4.47
4.56
C. There is a significant difference in mean brand value between financial institutions and telecom brands.
2.77
3.31
3.63
3.86
4.03
4.17
4.29
4.39
4.47
00
D. Because there is no significant difference among the groups, the Tukey-Kramer procedure is not appropriate.
Denominator,
Numerator, df
df
3
4
5
6.
7
10
Or 0o o
O O
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