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A researchers titrated a 100 mL solution of 0.1 M glycine at pH 1.72 with 2 M NaOH solution. She then monitored the pH and plotted the results in the graph shown here. The key points in the titration are designated I through V. 12 10 8 pH 6 4 2 0 11.30 9.60 5.97 2.34 ((1) 1 (II) 0.5 (III) 1.0 (IV) 1.5 OH-(equivalents) (V) 2.0

A researchers titrated a 100 mL solution of 0.1 M glycine at pH 1.72 with 2 M NaOH solution. She then monitored the pH and plotted the results in the graph shown here. The key points in the titration are designated I through V. 12 10 8 pH 6 4 2 0 11.30 9.60 5.97 2.34 ((1) 1 (II) 0.5 (III) 1.0 (IV) 1.5 OH-(equivalents) (V) 2.0

Chemical Principles in the Laboratory
Chemical Principles in the Laboratory
11th Edition
ISBN:9781305264434
Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Chapter24: The Standardization Of A Basic Solution And The Determination Of The Molar Mass Of An Acid
Section: Chapter Questions
Problem 2ASA: In an acid-base titration, 21.16 mL of an NaOH solution are needed to neutralize 20.04 mL of a...
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For each of the statements, identify the appropriate key point (I, II, III, IV, or V) in the titration.

A researchers titrated a 100 mL solution of 0.1 M glycine at pH 1.72 with 2 M NaOH solution. She then monitored the pH and plotted the results in the graph shown here. The key points in the titration are designated I through V. 12 10 8 pH 6 4 2 0 11.30 9.60 5.97 2.34 (1) 1 1 (II) 0.5 (III) 1 | 1 (IV) 1 1 1.0 1.5 OH- (equivalents) (V) I 2.0
Transcribed Image Text:A researchers titrated a 100 mL solution of 0.1 M glycine at pH 1.72 with 2 M NaOH solution. She then monitored the pH and plotted the results in the graph shown here. The key points in the titration are designated I through V. 12 10 8 pH 6 4 2 0 11.30 9.60 5.97 2.34 (1) 1 1 (II) 0.5 (III) 1 | 1 (IV) 1 1 1.0 1.5 OH- (equivalents) (V) I 2.0
The pH is equal to the pK₁ of the carboxyl group. The pH is equal to the pKa of the protonated amino group. The predominant glycine species is *H₂N-CH₂-COOH. The predominant glycine species is *H₂N-CH₂-COO™. Glycine predominantly exists as a 50:50 mixture of *H₂N-CH₂-COOH and *H₂N-CH₂-COO™.
Transcribed Image Text:The pH is equal to the pK₁ of the carboxyl group. The pH is equal to the pKa of the protonated amino group. The predominant glycine species is *H₂N-CH₂-COOH. The predominant glycine species is *H₂N-CH₂-COO™. Glycine predominantly exists as a 50:50 mixture of *H₂N-CH₂-COOH and *H₂N-CH₂-COO™.
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