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A researchers titrated a 100 mL solution of 0.1 M glycine at pH 1.72 with 2 M NaOH solution. She then monitored the pH and plotted the results in the graph shown here. The key points in the titration are designated I through V. 12 10 9.60 8 pH 6 4 11.30 2 5.97 2.34 (1) (II) 0.5 › (III) (IV) I 1.0 1.5 OH (equivalents) (V) 2.0

A researchers titrated a 100 mL solution of 0.1 M glycine at pH 1.72 with 2 M NaOH solution. She then monitored the pH and plotted the results in the graph shown here. The key points in the titration are designated I through V. 12 10 9.60 8 pH 6 4 11.30 2 5.97 2.34 (1) (II) 0.5 › (III) (IV) I 1.0 1.5 OH (equivalents) (V) 2.0

Chemical Principles in the Laboratory
Chemical Principles in the Laboratory
11th Edition
ISBN:9781305264434
Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Chapter24: The Standardization Of A Basic Solution And The Determination Of The Molar Mass Of An Acid
Section: Chapter Questions
Problem 2ASA: In an acid-base titration, 21.16 mL of an NaOH solution are needed to neutralize 20.04 mL of a...
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For each of the statements, identify the appropriate key point(s) (I, II, III, IV, V) in the titration.

A researchers titrated a 100 mL solution of 0.1 M glycine at pH 1.72 with 2 M NaOH solution. She then monitored the pH and plotted the results in the graph shown here. The key points in the titration are designated I through V. 12 10 8 pH 6 4 2 11.30 9.60 5.97 2.34 (II) I 0.5 (III) (IV) 1.0 1.5 OH- (equivalents) (V) 2.0
Transcribed Image Text:A researchers titrated a 100 mL solution of 0.1 M glycine at pH 1.72 with 2 M NaOH solution. She then monitored the pH and plotted the results in the graph shown here. The key points in the titration are designated I through V. 12 10 8 pH 6 4 2 11.30 9.60 5.97 2.34 (II) I 0.5 (III) (IV) 1.0 1.5 OH- (equivalents) (V) 2.0
For each of the statements, identify the appropriate key point(s) in the titration. The average net charge of glycine is +1. Half of the amino groups are ionized. The average net charge of glycine is 0. The average net charge of glycine is -1. This is the isoelectric point for glycine. Glycine has its maximum buffering capacity at these points.
Transcribed Image Text:For each of the statements, identify the appropriate key point(s) in the titration. The average net charge of glycine is +1. Half of the amino groups are ionized. The average net charge of glycine is 0. The average net charge of glycine is -1. This is the isoelectric point for glycine. Glycine has its maximum buffering capacity at these points.
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