A safety engineer records the braking distances of two types of tires. Each randomly selected sample has 35 tires. The results of the tests are shown in the figure. At a = 0.10, can the engineer support the claim that the mean braking distance is different for the two types of tires? Assume the samples are randomly selected and that the samples are independent. Туре А Туре в x, - 44 feet s, = 4.8 feet X, = 45 feet $2 = 4.7 feet (a) Identífy the claim and state Ho and Hg. What is the claim? O A. The mean braking distance is less for Type A tires than Type B tires. O B. The mean braking distance is different for the two types of tires. OC. The mean braking distance is the same for the two types of tires. O D. The mean braking distance is greater for Type A tires than Type B tires. What are Ho and H,? O A. Hg: H > H2 OC. Hg: H = H2 B. Hg: H SH2 Ha: H1 > H2 O E. Hg: Hy ZH2 Ha: H1 SH2 O D. Ho: H

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Туре в
A safety engineer records the braking distances of two types of tires. Each randomly selected sample has 35 tires. The results of the tests
are shown in the figure. At a = 0.10, can the engineer support the claim that the mean braking distance is different for the two types of tires?
Assume the samples are randomly selected and that the samples are independent.
Туре А
x, = 45 feet
S2 = 4.7 feet
= 44 feet
S, = 4.8 feet
(a) Identify the claim and state Hg and Hg.
What is the claim?
A. The mean braking distance is less for Type A tires than Type B tires.
B. The mean braking distance is different for the two types of tires.
C. The mean braking distance is the same for the two types of tires.
D. The mean braking distance is greater for Type A tires than Type B tires.
What are Ho and Ha?
OC. Hg: H1 = H2
A. Hg: H >H2
Ha: H1 SH2
B. Hg: H1 SH2
Ha: H1 > H2
Hạ: H1 * H2
OF. Hg: H1 * H2
Ha: H1 = H2
D. Ho: H1 <H2
E. Ho: H1 Z H2
Decide whether to reject or fail to reject the null hypothesis. Choose the correct answer below.
O A. Fail to reject Ho. The standardized test statistic falls in the rejection region.
B. Reject Hg. The standardized test statistic does not fall in the rejection region.
C. Fail to reject Hg. The standardized test statistic does not fall in the rejection region.
O D. Reject Ho. The standardized test statistic falls in the rejection region.
Interpret the decision in the context of the original claim.
At the% significance level, there is
evidence to
the claim that the mean braking distance for Type A tires is
Туре В tires.
Transcribed Image Text:Туре в A safety engineer records the braking distances of two types of tires. Each randomly selected sample has 35 tires. The results of the tests are shown in the figure. At a = 0.10, can the engineer support the claim that the mean braking distance is different for the two types of tires? Assume the samples are randomly selected and that the samples are independent. Туре А x, = 45 feet S2 = 4.7 feet = 44 feet S, = 4.8 feet (a) Identify the claim and state Hg and Hg. What is the claim? A. The mean braking distance is less for Type A tires than Type B tires. B. The mean braking distance is different for the two types of tires. C. The mean braking distance is the same for the two types of tires. D. The mean braking distance is greater for Type A tires than Type B tires. What are Ho and Ha? OC. Hg: H1 = H2 A. Hg: H >H2 Ha: H1 SH2 B. Hg: H1 SH2 Ha: H1 > H2 Hạ: H1 * H2 OF. Hg: H1 * H2 Ha: H1 = H2 D. Ho: H1 <H2 E. Ho: H1 Z H2 Decide whether to reject or fail to reject the null hypothesis. Choose the correct answer below. O A. Fail to reject Ho. The standardized test statistic falls in the rejection region. B. Reject Hg. The standardized test statistic does not fall in the rejection region. C. Fail to reject Hg. The standardized test statistic does not fall in the rejection region. O D. Reject Ho. The standardized test statistic falls in the rejection region. Interpret the decision in the context of the original claim. At the% significance level, there is evidence to the claim that the mean braking distance for Type A tires is Туре В tires.
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