Question
Asked Nov 15, 2019
2 views
A sample of 2.4 kg of Lead is at a temperature of 20C. 154 kJ of energy is added to the lead. What is the phase and temperature of the resulting sample?
check_circle

Expert Answer

Step 1

Consider the lead of mass m having specific heat capacity c and Ti and Tf are the initial and the final temperature of the lead.

Let the heat added is denoted by ΔQ.

m 2.4 kg
c 130 J/kgK
с
AQ=+154 kJ
T, 20° C
help_outline

Image Transcriptionclose

m 2.4 kg c 130 J/kgK с AQ=+154 kJ T, 20° C

fullscreen
Step 2

Write the formula for heat and plug the required values to det...

AQ me (T,-T)
f
ΔΟ
T=
T
f
тс
1000 J
(154 kJ)
lkJ
+(20 °C)
(2.4 kg)(130 J/kgK)
T, 493.59 K+(20 °C)
T, (493.59 -273.15)C+(20 °C)
11
f
T,-240.44 °C
help_outline

Image Transcriptionclose

AQ me (T,-T) f ΔΟ T= T f тс 1000 J (154 kJ) lkJ +(20 °C) (2.4 kg)(130 J/kgK) T, 493.59 K+(20 °C) T, (493.59 -273.15)C+(20 °C) 11 f T,-240.44 °C

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Science

Physics

Thermodynamics