A sample of 900 computer chips revealed that 48 % of the chips fail in the first 1000 hours of their use. The company's promotional literature claimed that 52% fail in the first 1000 hours of their use. Is there sufficient evidence at the 0.02 level to dispute the company's claim? State the null and alternative hypotheses for the above scenario.
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A: Given, p=0.48 x=10 n=22 p^=xn=1022=0.454545
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Q: A marriage counselor has traditionally seen that the proportion p of all married couples for…
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Q: A marriage counselor has traditionally seen that the proportion p of all married couples for whom…
A: From the provided information, Sample size (n) = 245 From which 189 of them stayed together. Sample…
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A: From the provided information,Sample size (n) = 210From which 167 of them stayed together.Level of…
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A: given data clim : p > 0.76n = 215x = 171α = 0.05p^ = xn = 171215 = 0.7953
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A: The hypothesized proportion is 0.16.
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Q: The power of the sample to detect the observed difference in population proportions (a = 0.05,…
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A: Given data, n=140 x=51 P=27.1% sample proportion(p)=x/n= 51/140 =0.3643
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A: Given n1=100n2=100p1^=20%=20100=0.2p2^=30% =30100=0.3
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A: Given: n= 400 ,x= 52.0 p= 0.112 ,significance level(∝)= 0.05 p̂= 52.0 / 400
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Q: A marriage counselor has traditionally seen that the proportion p of all married couples for whom…
A: Given that Sample size n =205 Favorable cases x =171 Sample proportion p^=x/n =171/205 =0.8341
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- "At a certain college, it is estimated that about 65% of the students have cars on campus, and with this number, the parking lot is fully occupied. Would you suggest to increase the parking lot space if, in a random sample of 61 college students, 44 are found to have cars? Use 0.01 level of significance." A There is sufficent evidence to say that there is a need to increase the parking lot space. No sufficient data to make a conclusion. "Certainly, the parking lot is enough." It is safe to assume that the parking lot is enoughA marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 77%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 77% of married couples. In a random sample of 250 married couples who completed her program, 194 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor's claim at the 0.10 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H₁. H₁:0 H₁ :0 (b) Determine the type of test statistic to use. (Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.) 0 (e) Is there enough…A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 80%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 80% of married couples. In a random sample of 215 married couples who completed her program, 180 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor’s claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. A. State the null hypothesis Hoand the alternative hypothesis H1. Ho: H1: B. Find the value of the test statistic. (Round to three or more decimal places.) C. Find the critical value. (Round to three or more decimal places.) D. Is there enough evidence to support the marriage counselor's claim that the proportion of married couples for whom her program…
- Previously, 3% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 3% today. She randomly selects 145 pregnant mothers and finds that 3 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a = 0.1 level of significance. What are the null and alternative hypotheses? Họ: P = 0.03 versus H4: p < 0.03 (Type integers or decimals. Do not round.) Because npo (1- Po) =|| 10, the normal model V be used to approximate the P-value. (Round to one decimal place as needed.)A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 79%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 79% of married couples. In a random sample of 250 married couples who completed her program, 205 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor's claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H₁. H₂ : D H₁ : 0 (b) Determine the type of test statistic to use. (Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.) 0 (e) Is there enough…A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 77%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 77% of married couples. In a random sample of 215 married couples who completed her program, 167 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor’s claim at the 0.10 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H0 and the alternative hypothesis H1. H0: H1: (b) Determine the type of test statistic to use. ▼(Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) (d) Find the p-value. (Round to three…
- A newsletter publisher believes that more than 79% of their readers own a personal computer. Is there sufficient evidence at the 0.02 level to substantiate the publisher's claim? State the null and alternative hypotheses for the above scenario.A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 78%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 78% of married couples. In a random sample of 240 married couples who completed her program, 189 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor’s claim at the 0.10 level of significance?Perform a one-tailed test. Then complete the parts below.A hospital director believes that above 55% of the lab reports contain errors and feels an audit is required. A sample of 120 reports found 72 errors. Is there sufficient evidence at the 0.02 level to substantiate the hospital director's claim? State the null and alternative hypotheses for the above scenario.
- According to securelist, 71.8% of all email sent is spam. A system manager at a large corporation believs that the percentage at his company may be 80%. he examines a random sample of 500 emails received at an email server, and finds that 382 of the messages are spam. a. State the appropriate null and alternate hypotheses. b. Compute the test statistic z. c. Using a=0.5 can you conclude the percentage of emails that are spam differs from 80%?According to the national Center for health statistics, 74% of American women have been married by the age of 30. Suppose in a survey of 125 American women ( who are at least 30) and it is found that 91 of them were married at least once. Does the survey provide significant evidence that less than 74% of American women have been married by the age of 30? Test the relevant hypotheses at a significance level of 0.10.A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 75%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 75% of married couples. In a random sample of 245 married couples who completed her program, 185 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor's claim at the 0.01 level of significance? (a) State the null hypothesis Ho and the alternative hypothesis H₁. Ho Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) H₁ (b) Determine the type of test statistic to use. (Choose one) ▼ (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.) (e) Is there enough…