A sample of iron ore weighing 0.962 g was dissolved in dilute acid solution, and all the Fe(II) was converted to Fe(III) ions. The solution required 32.32 mL of 0.0475M KMnO4 for titration. Fill in the table and calculate the % by mass of iron in the ore. Balance the equation: Fe +2 + MnO4 → Fe+3 + MnO2 Computation Name of analyte Iron ore Mass of analyte 0.2792 g Name of titrant KMnO4 Volume of titrant 23.30 mL Milliequivalents of the titrant 2.260 milliequivalents Mass of the analyte 0.125 g % Fe in analyte 44.81%

Chemistry: Principles and Practice
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Chapter18: Electrochemistry
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Problem 18.103QE
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A sample of iron ore weighing 0.962 g was dissolved in dilute acid solution, and all the Fe(II)
was converted to Fe(III) ions. The solution required 32.32 mL of 0.0475M KMnO4 for titration.
Fill in the table and calculate the % by mass of iron in the ore.
Balance the equation: Fe +2 +
MnO4 → Fe+3 + MnO2
Computation
Name of analyte
Iron ore
Mass of analyte
0.2792 g
Name of titrant
KMnO4
Volume of titrant
23.30 mL
Milliequivalents of the
titrant
2.260
milliequivalents
Mass of the analyte
0.125 g
% Fe in analyte
44.81%
Transcribed Image Text:A sample of iron ore weighing 0.962 g was dissolved in dilute acid solution, and all the Fe(II) was converted to Fe(III) ions. The solution required 32.32 mL of 0.0475M KMnO4 for titration. Fill in the table and calculate the % by mass of iron in the ore. Balance the equation: Fe +2 + MnO4 → Fe+3 + MnO2 Computation Name of analyte Iron ore Mass of analyte 0.2792 g Name of titrant KMnO4 Volume of titrant 23.30 mL Milliequivalents of the titrant 2.260 milliequivalents Mass of the analyte 0.125 g % Fe in analyte 44.81%
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