A satellite of mass m = 3.94e + 3 kg is in circular orbit around the Earth, and the radius of this orbit is ro = 1.04e + 4 km. Take th mass of the Earth to be ME = 6 × 1024 kg. The satellite is subject to a small frictional force of magnitude f = 0.0269 N due to the outer atmosphere of the Earth. Because of this force, the satellite will slowly spiral back towards Earth. What is the change in radius Ar of the satellite after one revolution (assuming the starting radius is ro as given above)? Hint: Assume that the change in radius is slow enough that at any instant of the orbit the satellite can be considered to be undergoing circular motion. Also, since this change in radius will be small, in the sense that A«1, you may (and should) use a Taylor expansion to find a close (i.e., first-order) approximation to the exact answer. Note: You should take Newton's constant to be G 6.674 x 1011 Nkg-2m?
Gravitational force
In nature, every object is attracted by every other object. This phenomenon is called gravity. The force associated with gravity is called gravitational force. The gravitational force is the weakest force that exists in nature. The gravitational force is always attractive.
Acceleration Due to Gravity
In fundamental physics, gravity or gravitational force is the universal attractive force acting between all the matters that exist or exhibit. It is the weakest known force. Therefore no internal changes in an object occurs due to this force. On the other hand, it has control over the trajectories of bodies in the solar system and in the universe due to its vast scope and universal action. The free fall of objects on Earth and the motions of celestial bodies, according to Newton, are both determined by the same force. It was Newton who put forward that the moon is held by a strong attractive force exerted by the Earth which makes it revolve in a straight line. He was sure that this force is similar to the downward force which Earth exerts on all the objects on it.
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