A scuba diver makes a slow descent into the depths of the ocean. His vertical position with respect to a boat on the surface changes several times. He makes the first stop 8.0 m from the boat but has a problem with equalizing the pressure, so he ascends 5.0 m and then continues descending for another 12.0 m to the second stop. From there, he ascends 5.0 m and then descends for 14.0 m, ascends again for 7.0 m and descends again for 12.0 m, where he makes a stop, waiting for his buddy. Assuming the positive direction up to the surface (+ĵ), express his net vertical displacement vector (in m) in terms of the unit vector ĵ. (Express your answer in vector form.)
A scuba diver makes a slow descent into the depths of the ocean. His vertical position with respect to a boat on the surface changes several times. He makes the first stop 8.0 m from the boat but has a problem with equalizing the pressure, so he ascends 5.0 m and then continues descending for another 12.0 m to the second stop. From there, he ascends 5.0 m and then descends for 14.0 m, ascends again for 7.0 m and descends again for 12.0 m, where he makes a stop, waiting for his buddy. Assuming the positive direction up to the surface (+ĵ), express his net vertical displacement vector (in m) in terms of the unit vector ĵ. (Express your answer in vector form.)
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter2: Vectors
Section: Chapter Questions
Problem 25P: A scuba diver makes a slow descent into the depths of the ocean. His vertical position with respect...
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A scuba diver makes a slow descent into the depths of the ocean. His vertical position with respect to a boat on the surface changes several times. He makes the first stop 8.0 m from the boat but has a problem with equalizing the pressure, so he ascends 5.0 m and then continues descending for another 12.0 m to the second stop. From there, he ascends 5.0 m and then descends for 14.0 m, ascends again for 7.0 m and descends again for 12.0 m, where he makes a stop, waiting for his buddy. Assuming the positive direction up to the surface (+ĵ), express his net vertical displacement vector (in m) in terms of the unit vector ĵ. (Express your answer in vector form.)
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