(A,) See the figure below. There are two torques applied at B and D. Segment CD is a tube, while AB and BC are solid rods. The cross-sections are shown in the figure, with Ro being the outer radius and Ri the inner radius. AB is made of an aluminum alloy (GaB = 4000 ksi) and BD is made of a steel alloy (Gup = 11000 ksi).

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter3: Torsion
Section: Chapter Questions
Problem 3.4.14P: A uniformly tapered tube AB with a hollow circular cross section is shown in the figure. The tube...
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*) See the figure below. There are two torques applied at B and D. Segment CD is a tube,
while AB and BC are solid rods. The cross-sections are shown in the figure, with Ro being the
outer radius and Ri the inner radius. AB is made of an aluminum alloy (GAB = 4000 ksi) and BD
is made of a steel alloy (GBD = 11000 ksi).
O Find the internal torque throughout the member.
Find the maximum shear stress tmax in the member between A and C.
Note: i) you have to show why that is Tmax, and how you find it.
ii) Do not calculate t in CD, since it is NOT requested.
Find the angle of twist 0 of the cross-section D relative to cross-section B.
Note: Do not calculate angle of twist in AB, since it is NOT requested.
1)
2)
3)
Ro = 4"
Ri = 2"
Ro = 4"
Ro = 2"
Cross-section:
40 Ib-ft
30 Ib-ft
5 ft
1 ft
3 ft
Transcribed Image Text:*) See the figure below. There are two torques applied at B and D. Segment CD is a tube, while AB and BC are solid rods. The cross-sections are shown in the figure, with Ro being the outer radius and Ri the inner radius. AB is made of an aluminum alloy (GAB = 4000 ksi) and BD is made of a steel alloy (GBD = 11000 ksi). O Find the internal torque throughout the member. Find the maximum shear stress tmax in the member between A and C. Note: i) you have to show why that is Tmax, and how you find it. ii) Do not calculate t in CD, since it is NOT requested. Find the angle of twist 0 of the cross-section D relative to cross-section B. Note: Do not calculate angle of twist in AB, since it is NOT requested. 1) 2) 3) Ro = 4" Ri = 2" Ro = 4" Ro = 2" Cross-section: 40 Ib-ft 30 Ib-ft 5 ft 1 ft 3 ft
Expert Solution
Step 1

In the given problem, the dimensions and Modulus of rigidity have been converted to feet.

Radius, 4in= 0.33ft

Radius, 2in=0.34ft

Modulus of rigidity in BD= 11000=1584000000lb/ft2

The complete solution has been attached.

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