A sex-influenced trait in humans affects the length of the index finger. A short allele is dominant in males and recessive in females.Heterozygous males have an index finger that is significantly shorterthan the ring finger. The gene affecting index finger length is locatedon an autosome. A woman with short index fingers has childrenwith a man who has normal index fingers. They produce five children in the following order: female, male, male, female, male. Theoldest female offspring has one daughter with a man who has normal fingers. The youngest male among the five children has childrenwith a woman with short index fingers; they have two sons. Drawthe pedigree for this family. Indicate the phenotypes of every individual (filled symbols for individuals with short index fingers andopen symbols for individuals with normal index fingers)

A sex-influenced trait in humans affects the length of the index finger. A short allele is dominant in males and recessive in females.Heterozygous males have an index finger that is significantly shorterthan the ring finger. The gene affecting index finger length is locatedon an autosome. A woman with short index fingers has childrenwith a man who has normal index fingers. They produce five children in the following order: female, male, male, female, male. Theoldest female offspring has one daughter with a man who has normal fingers. The youngest male among the five children has childrenwith a woman with short index fingers; they have two sons. Drawthe pedigree for this family. Indicate the phenotypes of every individual (filled symbols for individuals with short index fingers andopen symbols for individuals with normal index fingers)

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Description: A sex-influenced trait in humans affects the length of the index finger. A short allele is dominant in males and recessive in females.Heterozygous males have an index finger that is significantly shorterthan the ring finger. The gene affecting index

Biology Today and Tomorrow without Physiology (MindTap Course List)

5th Edition

ISBN:9781305117396

Author:Cecie Starr, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Christine Evers, Lisa Starr

Chapter9: Patterns Of Inheritance

Section: Chapter Questions

Problem 5SQ

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A sex-influenced trait in humans is one that affects the length of the index finger. A “short” allele is dominant in males and recessive in females. Heterozygous males have an index finger that is significantly shorter than the ring finger. The gene affecting index finger length is located on an autosome. A woman with short index fingers has children with a man who has normal index fingers. They produce five children in the following order: female, male, male, female, male. The oldest female offspring marries a man with normal fingers and then has one daughter. The youngest male among the five children marries a woman with short index fingers, and then they have two sons. Draw the pedigree for this family. Indicate the phenotypes of every individual (filled symbols for individuals with short index fingers and open symbols for individuals with normal index fingers).
In humans, the genes for colorblindness and hemophilia are both located on the X chromosome with no corresponding gene in the Y. These are both recessive alleles. If a man and a woman, both with normal vision, marry and have a colorblind son, draw the Punnet square that illustrates this. If the man dies and the woman remarries a colorblind man, draw a Punnet Square showing the type of children that could be expected from the second marriage. How many/what percentages of each could be expected.
A gene that controls the ability to see red and green is located on the X chromosome but not on the Y chromosome. There is a recessive nonfunctional allele for this gene that can cause red-green color blindness if the person possessing it does not also have the dominant normal gene. Consider the case of a carrier mother who is heterozygous for the red-green vision gene and a father who has normal vision. Use XB = normal vision, Xb = color-blind vision. What is the chance the parents would have a color-blind boy? A color-blind girl? What about a girl or boy with normal vision? Redo the Punnett square for a carrier mother (XBXb) and a color-blind father (XbY). Do the chances of having color-blind children change? How?
In humans, blue eyes are inherited as a recessive autosomal trait and color blindness is an X-linked recessive trait. A woman with blue eyes and normal color vision (her father was colorblind) marries a man who has normal color vision. The man has brown eyes, but his mother had blue eyes. What is the probability that this couple will have a son with brown eyes? What is the probability that this couple will have a color blind son with blue eyes?
A type of red-green colorblindness is inherited recessively on the X chromosome. A woman who is a carrier had children with a male that is not affected by the disease. Show your answers with the use of a Punnett square • What is the probability (% or likelihood) that a child is affected by the disease? • What is the probability (% or likelihood) that a son is a carrier? (Careful!) • Is there a chance that a girl of the couple is affected by the disease?
In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the genotype of the woman's father? What is the probability that the couple's first child will be a non-freckled, normal visioned girl? What is the probability that the first two children born to the couple will be freckled and colorblind girls?
Suppose gene B is X-linked and is embryonically lethal when homozygous or hemizygous recessive. A man marries a woman who is heterozygous for this gene. They want to have three kids – one girl and two boys. Using a Punnett square, answer the following: What is the probability that they will have a son that dies before birth? _______________________ What is the probability that they will have a daughter who has the same genotype as her mother? _________________ One of their daughters eventually has a child with a man. One of their sons dies before birth. What was the genotype of this daughter? _______________________________ please show me how to get the answer and explain how you got and use a punnet square
In the following pedigree of an X-linked recessive trait, what is the likelihood a child will be affected for the following matings? 1 x 2 [___] 13 x 14 [_____] 2 x 14 [_______] 4 x 12. [_______]
Men have XY (or YX) chromosomes and women have XX chromosomes. X-linked recessive genetic diseases (such as juvenile retinoschisis) occur when there is a defective X chromosome that occurs without a paired X chromosome that is not defective. Represent a defective X chromosome with lowercase x, so a child with the xY or Yx pair of chromosomes will have the disease and a child with XX or XY or YX or xX or Xx will not have the disease. Each parent contributes one of the chromosomes to the child. Complete parts a through d below. a. If a father has the defective x chromosome and the mother has good XX chromosomes, what is the probability that a son will inherit the disease? nothing (Type an integer or a decimal. Do not round.) b. If a father has the defective x chromosome and the mother has good XX chromosomes, what is the probability that a daughter will inherit the disease? nothing (Type an integer or a decimal. Do not round.) c. If a mother has one defective x…
Alleles of a single gene control whether individuals have a "hitchhiker's thumb" or "straight thumb." You are studying the inheritance of hitchhiker's thumb (straight thumb is dominant) in your family. Assuming that this trait is inherited on an autosome (ie, not a sex-chromosome), please answer which of the following outcomes ARE POSSIBLE under normal circumstances. (Choose all that apply.) 1) Two parents have straight thumb, but they have a child with hitchhiker's thumb. 2) Two parents have hitchhiker's thumb, but they have a child with straight thumb. 3) Mother has straight thumb, father has hitchhiker's thumb, child is homozygous dominant for the allele. 4) Mother has straight thumb, father has hitchhiker's thumb. They have one child with straight thumb, another child with hitchhiker's thumb.
In humans, the gene for albinism (a) is recessive to the gene for normal skin pigmentation (A). If two heterozygous persons have children, what is the probability they will have a child who is an albino? What is the probability they will have a child that is a carrier of the recessive gene?
Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___