A simple random sample of 28 filtered 100-mm cigarettes is obtained from a normally distributed population, and the tar content of each cigarette is measured. The sample has a standard deviation of 0.22 mg. Use a 0.05 significance level to test the claim that the tar content of filtered 100-mm cigarettes has a standard deviation different from 0.35 mg, which is the standard deviation for unfiltered king-size cigarettes. Complete parts (a) through (d) below. a. What are the null and alternative hypotheses? O A. Ho: o = 0.35 mg H,: o<0.35 mg B. Ho: o = 0.35 mg H:0+0.35 mg O C. Ho: o > 0.35 mg O D. Ho: o + 0.35 mg H1: o = 0.35 mg H1:os0.35 mg

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Find the test statistic.

Find the​ P-value of the test statistic.

State the conclusion.

A simple random sample of 28 filtered 100-mm cigarettes is obtained from a normally distributed population, and the tar
content of each cigarette is measured. The sample has a standard deviation of 0.22 mg. Use a 0.05 significance level to test
the claim that the tar content of filtered 100-mm cigarettes has a standard deviation different from 0.35 mg, which is the
standard deviation for unfiltered king-size cigarettes. Complete parts (a) through (d) below.
a. What are the null and alternative hypotheses?
O A. Ho: o = 0.35 mg
H,: o<0.35 mg
B. Ho: o = 0.35 mg
H,: o#0.35 mg
O C. Ho: o> 0.35 mg
H1: os0.35 mg
OD.
o+0.35 mg
H1: 0 = 0.35 mg
b. Find the test statistic.
(Round to three decimal places as needed.)
Transcribed Image Text:A simple random sample of 28 filtered 100-mm cigarettes is obtained from a normally distributed population, and the tar content of each cigarette is measured. The sample has a standard deviation of 0.22 mg. Use a 0.05 significance level to test the claim that the tar content of filtered 100-mm cigarettes has a standard deviation different from 0.35 mg, which is the standard deviation for unfiltered king-size cigarettes. Complete parts (a) through (d) below. a. What are the null and alternative hypotheses? O A. Ho: o = 0.35 mg H,: o<0.35 mg B. Ho: o = 0.35 mg H,: o#0.35 mg O C. Ho: o> 0.35 mg H1: os0.35 mg OD. o+0.35 mg H1: 0 = 0.35 mg b. Find the test statistic. (Round to three decimal places as needed.)
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