A skateboarder weighing 74.26 kg goes over a smooth circular hill. If the skateboarder's speed at point A is 42.21 m/s, what is his speed at the top of the hill (point B)? Use g=9.8 m/s2 . Derive first the working equation before you substitute the given data to avoid disparity from the correct answer. Round off answer up to two decimal places. Include the unit/s. Abbreviation only. A skateboarder weighing 74.26 kg goes over a smooth circular hill. If the skateboarder'sspeed at point A is 42.21 m/s, what is his speed at the top of the hill (point B)?Use g=9.8 m/s2 . Derive first the working equation before you substitute thegiven data to avoid disparity from the correct answer.Round off answer up totwo decimal places. Include the unit/s. Abbreviation only.WEP Item 1АПhSВWEP Item 2BA10 m450

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Answered: A skateboarder weighing 74.26 kg goes…

A skateboarder weighing 74.26 kg goes over a smooth circular hill. If the skateboarder's speed at point A is 42.21 m/s, what is his speed at the top of the hill (point B)?

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter6: Motion In Two Dimensions

Section: Chapter Questions

Problem 62A

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Instantaneous Power

Power is defined in physics as the amount of energy transmitted or transformed per unit time. The watt is the unit of electricity in the International System of Units, equivalent to one joule per second.

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A skateboarder weighing 74.26 kg goes over a smooth circular hill. If the skateboarder's speed at point A is 42.21 m/s, what is his speed at the top of the hill (point B)?

Use g=9.8 m/s² . Derive first the working equation before you substitute the given data to avoid disparity from the correct answer. Round off answer up to two decimal places. Include the unit/s. Abbreviation only.

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