A small 4 kg block is accelerated from rest on a flat surface by a compressed spring (k = 647 N/m) along a frictionless, horizontal surface. The block leaves the spring at the spring's equilibrium position (x = 0) and travels on an incline (0 = 30°) with a coefficient of kinetic friction µk = 0.25. The block moves a horizontal distance D = 8 m before coming to a stop. %3D

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter7: Conservation Of Energy
Section: Chapter Questions
Problem 71P
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Part 1 is correct, I just don’t know how to solve part 2. I think I use (1/2kx^2 = 1/2mv^2 but I’m not sure, What do I do with v?
A small 4 kg block is accelerated from rest on a flat surface by a compressed spring (k = 647 N /m) along a
frictionless, horizontal surface. The block leaves the spring at the spring's equilibrium position (x = 0) and
travels on an incline (0 = 30°) with a coefficient of kinetic friction µj = 0.25. The block moves a horizontal
distance D = 8 m before coming to a stop.
x = 0
D
Transcribed Image Text:A small 4 kg block is accelerated from rest on a flat surface by a compressed spring (k = 647 N /m) along a frictionless, horizontal surface. The block leaves the spring at the spring's equilibrium position (x = 0) and travels on an incline (0 = 30°) with a coefficient of kinetic friction µj = 0.25. The block moves a horizontal distance D = 8 m before coming to a stop. x = 0 D
Part 1
(a) What is the initial compression of the spring?
x =
0.878
Part 2
(b) What is the maximum kinetic energy of the block?
Kmax
number (rtol=0.05, atol=1e-08)
тат
Transcribed Image Text:Part 1 (a) What is the initial compression of the spring? x = 0.878 Part 2 (b) What is the maximum kinetic energy of the block? Kmax number (rtol=0.05, atol=1e-08) тат
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