300 g 1.2 m k = 500 N/m అనువము 30° 900 g

Q: A 2.00-kg pendulum ball is attached to a light-uniform cable of length 1.20 m that is hanging from…

A: Given Information:- Mass of the pendulum ball is  mP=2.00 kg. Length of the cable is l=1.20 m. The…

Q: A pendulum consists of a 2.0-kg block hanging on a 1.5-m length string. A 10-g bullet moving with a…

A: Given, mass of block mblock = 2 Kg Length of sting L = 1.5 m Mass od bullet mbullet = 10 g = 0.01 m…

Q: A light spring with force constant 3.10 N/m is compressed by 7.80 cm as it is held between a…

A: Mass of left block=m1=0.4 kg  Mass of right block=m2=0.8kg Let acceleration of m1=a1 m/s^2  and…

Q: A block of mass ? = 300 g is released from rest from the top of a frictionless ramp. At the bottom…

A: Given Data : The mass of the block is given as m = 300 g. The spring constant of the spring is given…

Q: A 2.00-kg pendulum ball is attached to a light-uniform cable of length 1.20 m that is hanging from…

A: When pendulum moves its total energy is conserved, hence Potential energy at A = Kinetic energy at B…

Q: A 1.0-kg block (m1) is attached to the end of a 2.5-m string to form a pendulum. This pendulum is…

A: Since you have posted a question with a multiple sub parts, we will solve first three sub - parts…

Q: pendulum consists of a 2.0 m long steel wire supporting a lentil of mass 20 kg. If the pendulum is…

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Q: 0.350 kg block of wood rests on a horizontal frictionless surface and is attached to a spring (also…

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Q: An object of mass m is dropped from the top of an inclined plane of height h and large Θ and…

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Q: A bullet with a mass mp = 12.7 g is fired into a block of wood at velocity vp = 257 m/s. The block…

A: We will solve the problem by using the principle ofconservation of linear momentum and then the…

Q: A bullet of mass 4 g moving with an initialspeed 300 m/s is fired into and passes througha block of…

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Q: You have been asked to design a "ballistic spring system" to measure the speed of bullets. A bullet…

A: m = 2.1 g M = 1.5 kg k = 40 N/m d = 0.15 m using conservation of energy (1/2)(M+m)(V)2 =…

Q: A mass m1 = 8.00 kg is in equilibrium while connected to a light spring of constant k = 155 N/m, as…

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Q: Question 1 k=163 N/m m=0.2kg d A A mass of m=0.2kg moves on a horizontal surface. The coefficient of…

A: Givenm =0.2 kgμk =0.1 Initial velocity =v0 =3.21 m/sFinal velocity = v' = 0.9 v0K =163 N/m

Q: 1. A ball having a mass of 60g is attached to the horizontal barrel of a spring gu The spring has a…

A: Given :-  K = 730 N/ m x = 50 mm = 50 × 10-3  m = 60 kg  F = 4 N

Q: A bullet with a mass m(b)=13.1 g is fired into a block of wood at velocity v(b)=261 m/s. The block…

A: Given, a bullet with a mass mb=13.1 g = 0.0131 kg is fired into a block of wood at velocity vb=261…

Q: In the ballistic pendulum shown below, the block has a mass of 1.7 kg, the bullet has a mass of…

A: Given M = 1.7 kgm = 0.0054 Kg L = 2.91 mθ = 26°

Q: T M k A block of mass m = 23.0 kg is at rest on a frictionless inclined plane with angle 0 = 40.0°.…

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Q: A 2.00-kg pendulum ball is attached to a light-uniform cable of length 1.20 m that is hanging from…

A: Mass of pendulum, m1=2.00 kgAngle with the vertical, θ=50.0°Length of cable, L=1.20 mMass of block,…

Q: Two steel balls are suspended by vertical strings (not necessarily of the same length), so that at…

A: This problem is based on the energy conservation. If one of steel ball touches the other when it…

Q: A ball of mass m = 1.80 kg is released from rest at a height h = 65.0 cm above a light vertical…

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Q: An 8.0 g bullet is shot into a 4.0 kg block that starts out at rest on a frictionless horizontal…

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Q: A massless spring (with force constant k = 194 N/m) connects a wall and a DIOCK of wood. The system…

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Q: I just need the last part of the question

A: According to work energy theorem, change in kinetic energy is equal to work done by spring and…

Q: Consider a simple wheelchair with a suspension system (bumper) composed of a spring and a dashpot as…

A: cdd2(y-x)k(y-x)free body diagrammay block Fm=ma=md2ydtv             fk=k(y-x)  fc=cddt(y-x)

Q: A brick of mass m = 0.48 kg is set against a spring with a spring constant of k1 = 619 N/m which has…

A: Given: m =0.48 kgk1=619 N/md1=0.1mk2=244 N/mμk=0.5x=1md2=?

Q: . A small balloon containing sand with a combined mass of 98.2gg is suspended with an ideal string…

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Q: A 0.430 kg block of wood rests on a horizontal frictionless surface and is attached to a spring…

A: Using conservation of momentum, mu=m+Mvv=umm+M

Q: A 5 kg box is attached to a spring that has an elastic coefficient of 110 N/m. The spring is…

A: The potential energy stored in the spring is  U = 0.5 K x2 where, K is the spring constant,, x is…

Q: You have been asked to design a "ballistic spring system" to measure the speed of bullets. A bullet…

A: From conservation of momentum is, mBvB=mB+Mvf       ......(i) From conservation of energy,…

Q: A massless spring (with force constant k = 189 N/m) connects a wall and a block of wood. The system…

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Q: A 1.30 kg block of wood sits on a frictionless horizontal surface is attached rigid support by a…

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Q: spring is initially compressed 0.5 m, and block A is released from rest, in the position shown in…

A: Energy stored in spring = (1/2)kx2   k = Force constant = 100 N/m In all collision momentum is…

Q: A 1.62 kg ball rolls on a frictionless horizontal surface at 4.59 m/s and collides with a stationary…

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Q: A 12.0-g bullet is fired horizontally into a 116-g wooden block that is initially at rest on a…

A: Mass of bullet M = 12.0 g = 0.012 kg  Mass of block M' = 116 g = 0.116 kg Spring constant k = 159…

Q: A .430 kg block is attached to a horizontal spring that is at its equilibrium length, and whose…

A: Given that, mass of block = m1=0.430 kgmass of putty=m2=0.05 Kginitial speed of putty = u2=2.30…

Q: Van Helsing shoots a 150g stake from a crossbow. Find the stake’s speed if we treat the crossbow as…

A: Here the system consists of stake and crossbow. Here we have to use the conservation of energy,…

Q: bullet with a mass mb=11.9 g is fired into a block of wood at velocity vb=245 m/s. The block is…

A: Apply conservation of momentum principle mbvb=mb+mwv11.9×10-3 kg245 ms=mb+mwv2.9155 kg ms=mb+mwv…

Q: A 0.454-kg block is attached to a horizontal spring that is at its equilibrium length, and whose…

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Q: A 2.50-kg uniform bar of length e = 1.30 m is held in a horizontal position by three vertical…

A: Given,

Q: A 10.0 g bullet is fired into and embeds itself in a 2.30 kg block attached to a spring with a…

A: From Conservation of momentum ,m1u1+m2u2=(m1+m2)V0+(0.01×300)=(0.01+2.3)VV =1.3 m/sVelocity of the…

Q: (v) In the figure-5.92 shown, the springs are unstretched. The left spring is compressed by 2A and…

A: The oscillation position of the spring is, x=Acosωt=2Acosωt…

Q: A 10.0 g bullet is fired into and embeds itself in a 1.60 kg block attached to a spring with a…

A: Given that, Mass of a bullet, m = 10 g = 0.01 kg Mass of a block, M = 1.6 kg The spring constant of…

Q: A 2.00-kg pendulum ball is attached to a light-uniform cable of length 1.20 m that is hanging from…

A:

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.