Question
Asked Mar 1, 2020
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A solution contains of 50.0g (0.532 mol) of heptane, C7H14(l) and 50.0g (0.468 mol) of octane, C8H18(l) at 25°C. At 25°C the vapor pressure of heptane is 45.8 torr, and that of pure octane is 10.9 torr. 

a) What are the mole fractions of the two components in the solution?

b) What are the vapor pressures of each component in the solution?

c) What is the total vapor pressure above the solution?

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Expert Answer

Step 1

Given:

Mass of heptane = 50.0 g

Moles of heptane = 0.532 mol

Mass of Octane = 50.0 g

Moles of Octane = 0.468 mol

vapor pressure of pure heptane = 45.8 torr

vapor pressure of pure octane = 10.9 torr

Step 2: Anwser-a

Calculation for mole fraction of heptane(C7H14):

Chemistry homework question answer, step 2, image 1

Calculation for mole fraction of Octane(C8H16):

Chemistry homework question answer, step 2, image 2

 

Step 3: Answer-b

Calculation for partial pressure of heptane(C7H14):

Chemistry homework question answer, step 3, image 1

Calculation for partial pressure of Octane(C8H16):

Chemistry homework question answer, step 3, image 2

 

...

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