A solution is created by dissolving 13.5 grams of ammonium chloride in enough water to make 225 mL of solution. a) How many moles of ammonium chloride are resent in the resulting solution?b) when thinking about the amount of solute present in a solution, chemist report the concentration or molarity of the solution. Molarity is calculated as moles of solute per liter of solution. What is the molarity of the solution above? c) to carry out a particular reactant, you determine that you need 0.0500 moles of ammonium chloride. What volume of the solution described above will you need to complete the reaction without any leftover NH4Cl?

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Asked Nov 19, 2019
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A solution is created by dissolving 13.5 grams of ammonium chloride in enough water to make 225 mL of solution. a)

 How many moles of ammonium chloride are resent in the resulting solution?

b) when thinking about the amount of solute present in a solution, chemist report the concentration or molarity of the solution. Molarity is calculated as moles of solute per liter of solution. What is the molarity of the solution above? 

c) to carry out a particular reactant, you determine that you need 0.0500 moles of ammonium chloride. What volume of the solution described above will you need to complete the reaction without any leftover NH4Cl? 

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