Question
Asked Oct 2, 2019
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A solution is prepared by mixing 3.34 mol of acetone with 1.45 mol of cyclohexane at 30°C.

 

Calculate the Xacetone and Xcyclohexane in the vapor above the solution.  
P°acetone = 229.5 torr and P°cyclohexane = 97.6 torr.

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Expert Answer

Step 1

The values are given as follows:

moles of acetone = 3.34 mol
moles of cyclohexane = 1.45 mol
-
total moles 3.34 mol + 1.45 mol
=4.79 mol
vapor pressure of acetone(Ptone ) = 229.5 torr
vapor pressure of cyclohexane(P cvelohexane ) =97.6 torr
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moles of acetone = 3.34 mol moles of cyclohexane = 1.45 mol - total moles 3.34 mol + 1.45 mol =4.79 mol vapor pressure of acetone(Ptone ) = 229.5 torr vapor pressure of cyclohexane(P cvelohexane ) =97.6 torr

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Step 2

The mole fraction of acetone in the solution can be calculated as follows:

(solution)= number of moles of acetone
total number of moles
х,
aceton
3.34 mol
4.79 mol
= 0.6973
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(solution)= number of moles of acetone total number of moles х, aceton 3.34 mol 4.79 mol = 0.6973

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Step 3

The mole fraction of cyclohexane in the sol...

number of moles of cyclohexane
Xeyclohexane (Solution)
total number of moles
1.45 mol
4.79 mol
=0.3027
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number of moles of cyclohexane Xeyclohexane (Solution) total number of moles 1.45 mol 4.79 mol =0.3027

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