A solution made with 0.140 moles of phosporic acid (H3PO4), dissolved in 194 mL of solution, was titrated with 1.320 M NaOH. How many mL of NaOH solution are necessary to reach a pH of 7.062?

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 58QAP: Water is accidentally added to 350.00 mL of a stock solution of 6.00 M HCI. A 75.00-mL sample of the...
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A solution made with 0.140 moles of phosporic acid (H3PO4), dissolved in 194 mL
of solution, was titrated with 1.320 M NAOH. How many mL of NAOH solution
are necessary to reach a pH of 7.062?
Volume of base (mL) =
171.877
2 x0%
Equations and Constants
Acids and Bases
pH = –log[H3O+]
pOH = -log[OH¯]
10-nH
11
10
Transcribed Image Text:A solution made with 0.140 moles of phosporic acid (H3PO4), dissolved in 194 mL of solution, was titrated with 1.320 M NAOH. How many mL of NAOH solution are necessary to reach a pH of 7.062? Volume of base (mL) = 171.877 2 x0% Equations and Constants Acids and Bases pH = –log[H3O+] pOH = -log[OH¯] 10-nH 11 10
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