A solution of HCl was titrated against sodium carbonate.What is the titer for Trial 1 in the given data?T20.35620.34790.3042Weight (g)Initial V (ml)0.801.6035.2036.7039.80Final V (ml)Vol HCI used (ml)35.10N of HC (eq/L)0.19540.1870Average N of HCl (eq/L)A

Given : Weight of Na2CO3 = 0.3562 gm Normality of HCl = 0.1954 N

A solution of HCl was titrated against sodium carbonate. What is the titer for Trial 1 in the given data? T1 T2 T3 0.3562 0.3479 0.3042 Weight (g) Initial V (mL) 0.80 1.60 0.40 Final V (ml) 35.20 36.70 39.80 Vol HCI used (ml) 35.10 39.40 N of HCI (eq/L) 0.1954 0.1870 Average N of HCl (eq/L) 91

A solution of HCl was titrated against sodium carbonate. What is the titer for Trial 1 in the given data? T1 T2 T3 0.3562 0.3479 0.3042 Weight (g) Initial V (mL) 0.80 1.60 0.40 Final V (ml) 35.20 36.70 39.80 Vol HCI used (ml) 35.10 39.40 N of HCI (eq/L) 0.1954 0.1870 Average N of HCl (eq/L) 91

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter21: Potentiometry

Section: Chapter Questions

Problem 21.22QAP

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Question

A solution of HCl was titrated against sodium carbonate.
What is the titer for Trial 1 in the given data?
T2
0.3562
0.3479
0.3042
Weight (g)
Initial V (ml)
0.80
1.60
35.20
36.70
39.80
Final V (ml)
Vol HCI used (ml)
35.10
N of HC (eq/L)
0.1954
0.1870
Average N of HCl (eq/L)
A

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