A space probe has two engines. Each generates the same amount of force when fired, and the directions of these forces can be independently adjusted. When the engines are fired simultaneously and each applies its force in the same direction, the probe, starting from rest, takes 31.2 s to travel a certain distance. How long does it take to travel the same distance, again starting from rest, if the engines are fired simultaneously and the forces that they apply to the probe are perpendicular?

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Asked Sep 29, 2019
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A space probe has two engines. Each generates the same amount of force when fired, and the directions of these forces can be independently adjusted. When the engines are fired simultaneously and each applies its force in the same direction, the probe, starting from rest, takes 31.2 s to travel a certain distance. How long does it take to travel the same distance, again starting from rest, if the engines are fired simultaneously and the forces that they apply to the probe are perpendicular?

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Expert Answer

Step 1

Given:

Time taken to travel a certain distance when both forces are in same direction = 31.2 s

Step 2

Calculating the time taken to travel the same distance if both the forces are perpendicu...

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the probe Lt the dis tauce traue|led 2- for frst care 2 t31-2 sec ,= (Fnct) whu m For inst Care, (fnet), - 2F (Forces arein same direction) (3 2 2 S= (312) F m For 2nd Care, 2 where an Enet)2 m fnet) (Fevees per penatiulan) Al o aue 2. So, 2 ea ond , 31-2 F Eequalithg Jam Hence, t (25 "x 31.2 Sec t 37 see

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Science

Physics

Newtons Laws of Motion

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