Case StudyA student has 27.8 grams of helium and reguires 6,89 moles for an experiment. Does me stadenhave enough helium for the experiment?To solve this problem, find the number of moles in 27.8 grams and compare it to the 6.89 motesavailable to determine if the student has sufficient helium for the reaction.I mole He27.8 grams He x= 6.95 moles He4.00g HeComparing the available 6.95 moles with the needed 6.89 moles, vou can conclude that thestudent has enough He for the reaction, with 0.06 moles left over.Note that the conversion factor between moles and grans can be expressed two ways:I moleatomic mass in gramsoratomic mass in grams1 moleHow do you know which conversion factor to use? Consider which unit you need and how unitscancel in a setup. If you need to know the numbin the numerator (on top). If you need to kmow the number of grams, use the conversion factorwith grams in the numerator.of moles, use the conversfactor with molesto ieCHEM 40 LAB MANUAL 2019 - 2020Page 156

Given : amount of He given = 27.8g moles of He required = 6.89 moles

A student has 27.8 grams of helium and requires 6,89 moles for an experiment. Does the sttdent have enough helium for the experiment? To solve this problem, find the number of moles in 27.8 grams and compare it to the 6.89 moles available to determine if the student has sufficient helium for the reaction.

A student has 27.8 grams of helium and requires 6,89 moles for an experiment. Does the sttdent have enough helium for the experiment? To solve this problem, find the number of moles in 27.8 grams and compare it to the 6.89 moles available to determine if the student has sufficient helium for the reaction.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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