A student has prepared a 0.05 M solution of C6H5-OH and has added to it a 0.05 M solution of di-iso-propylamine (HN(CH(CH3)2)2. Concentrations are given only to emphasize they are equal, you do not need the value itself.  (i) Write the equation for the acid-base reaction that might occur.  (ii) With curved arrows track the movements of electron pairs.  (iii) Assign Base, Acid, Conjugate acid for the base, Conjugate base for the acid.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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  1. A student has prepared a 0.05 M solution of C6H5-OH and has added to it a 0.05 M solution of di-iso-propylamine (HN(CH(CH3)2)2. Concentrations are given only to emphasize they are equal, you do not need the value itself. 

(i) Write the equation for the acid-base reaction that might occur. 

(ii) With curved arrows track the movements of electron pairs. 

(iii) Assign Base, Acid, Conjugate acid for the base, Conjugate base for the acid.

(iv) Calculate the percentage of phenolate (C6H5O-) that forms in this acid-base reaction taking into account that pKa of the conjugate acid of di-iso-propylamine equals 11 and pKa of phenol (C6H5OH) equals 10.

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