A student is told that a solution of 1.03 g of an unknown ionic compound dissolved in 10.0 g of water freezes at -1.64 oC. She is told to assume the solution has ideal behayior. She is also told the unknown is one of the compounds given below. Which of the ionic compounds isher unknown? The freezing point of water is 0 oC and Kf = 1.86 oC/m. Group of answer choices aluminum nitrate, Al(NO3)3 (MM = 213 g/mol) strontium perchlorate, Sr(CIO4)2 (MM = 286.6 g/mol) cesium iodide, Csl (MM = 259.8 g/mol) barium sulfate, BaSO4 (MM = 233.4 g/mol) Expert Answer O

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter13: Solutions And Their Behavior
Section: Chapter Questions
Problem 71GQ: An aqueous solution containing 10.0 g of starch per liter has an osmotic pressure of 3.8 mm Hg at 25...
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A student is told that a solution of 1.03 g of an unknown ionic compound dissolved in 10.0 g of water
freezes at -1.64 oC. She is told to assume the solution has ideal behayior. She is also told the unknown is
one of the compounds given below. Which of the ionic compounds isner unknown? The freezing point of
water is 0 oC and Kf = 1.86 oC/m.
Group of answer choices
aluminum nitrate, Al(NO3)3 (MM = 213 g/mol)
strontium perchlorate, Sr(CI04)2 (MM = 286.6 g/mol)
cesium iodide, Csl (MM = 259.8 g/mol)
barium sulfate, BaSO4 (MM = 233.4 g/mol)
%3D
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Transcribed Image Text:A student is told that a solution of 1.03 g of an unknown ionic compound dissolved in 10.0 g of water freezes at -1.64 oC. She is told to assume the solution has ideal behayior. She is also told the unknown is one of the compounds given below. Which of the ionic compounds isner unknown? The freezing point of water is 0 oC and Kf = 1.86 oC/m. Group of answer choices aluminum nitrate, Al(NO3)3 (MM = 213 g/mol) strontium perchlorate, Sr(CI04)2 (MM = 286.6 g/mol) cesium iodide, Csl (MM = 259.8 g/mol) barium sulfate, BaSO4 (MM = 233.4 g/mol) %3D Expert Answer o An expert answer will be posted here
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