SHOW SOLUTION A 0.7120 g of iron ore was brought into solution and passed through a Jones reductor. Titration of Fe(I1) produced required 39.21mL of 0.02086M KMnO4. Express the results of analysis in terms of (a) percent Fe (MM 55.85) and (b) percent Fe2O3 (MM 159.69). 5Fe+2 + MnO4 - + 8H+ → 5Fe+3 + Mn +2 + 4H2O Answer: 32.08% Fe, 45. 86% Fe2O3
SHOW SOLUTION A 0.7120 g of iron ore was brought into solution and passed through a Jones reductor. Titration of Fe(I1) produced required 39.21mL of 0.02086M KMnO4. Express the results of analysis in terms of (a) percent Fe (MM 55.85) and (b) percent Fe2O3 (MM 159.69). 5Fe+2 + MnO4 - + 8H+ → 5Fe+3 + Mn +2 + 4H2O Answer: 32.08% Fe, 45. 86% Fe2O3
Chapter17: Complexation And Precipitation Reactions And Titrations
Section: Chapter Questions
Problem 17.29QAP
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A 0.7120 g of iron ore was brought into solution and passed through a Jones reductor. Titration of Fe(I1) produced required 39.21mL of 0.02086M KMnO4. Express the results of analysis in terms of (a) percent Fe (MM 55.85) and (b) percent Fe2O3 (MM 159.69).
5Fe+2 + MnO4 - + 8H+ → 5Fe+3 + Mn +2 + 4H2O
Answer: 32.08% Fe, 45. 86% Fe2O3
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