A student set up a simple circuit with an ohmic lightbulb, battery and switch.When the switch is closed, the student measures 527mA being drawn from the 4.2V battery by the lightbulb. They decide to leave the switch closed for a few hours.When they measure the current again, they find it is now 397mA, and correctly guesses that the battery has dropped voltage. What would they measure the new voltage across the battery to be? (Units: V) A student set up a simple circuit with an ohmic lightbulb, battery and switch.batteryswitchlight bulbWhen the switch is closed, the student measures 527mA being drawn from the 4.2V battery by the lightbulb. They decide toleave the switch closed for a few hours.When they measure the current again, they find it is now 397MA, and correctly guesses that the battery has dropped voltage.What would they measure the new voltage across the battery to be? (Units: V)

Given: initial voltage = V1= 4.2 V initial current = I1= 527 mA voltage = V2= ? V Final current =…

Answered: A student set up a simple circuit with…

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter28: Direct-current Circuits

Section: Chapter Questions

Problem 28.63AP: The- pair of capacitors in Figure P28.63 are fully charged by a 12.0-V battery. The battery is...

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A student set up a simple circuit with an ohmic lightbulb, battery and switch.

When the switch is closed, the student measures 527mA being drawn from the 4.2V battery by the lightbulb. They decide to leave the switch closed for a few hours.

When they measure the current again, they find it is now 397mA, and correctly guesses that the battery has dropped voltage. What would they measure the new voltage across the battery to be? (Units: V)

A student set up a simple circuit with an ohmic lightbulb, battery and switch.
battery
switch
light bulb
When the switch is closed, the student measures 527mA being drawn from the 4.2V battery by the lightbulb. They decide to
leave the switch closed for a few hours.
When they measure the current again, they find it is now 397MA, and correctly guesses that the battery has dropped voltage.
What would they measure the new voltage across the battery to be? (Units: V)

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