   Chapter 17, Problem 41P

Chapter
Section
Textbook Problem

Lightbulb A is marked “25.0 W 120. V,” and lightbulb B is marked “100. W 120. V.” These labels mean that each lightbulb has its respective power delivered to it when it is connected to a constant 120.-V source. (a) Find the resistance of each lightbulb. (b) During what time interval does 1.00 C pass into lightbulb A? (c) Is this charge different upon its exit versus its entry into the lightbulb? Explain. (d) In what time interval does 1.00 J pass into lightbulb A? (e) By what mechanisms does this energy enter and exit the lightbulb? Explain. (f) Find the cost of running lightbulb A continuously for 30.0 days, assuming the electric company sells its product at \$0.110 per kWh.

(a)

To determine
The resistance of light bulb A and light bulb B.

Explanation

Given Info: The power delivered to light bulb A when connected to 120V source is 25W , The power delivered to bulb B is 100W when 120V is applied.

Explanation:

Formula to calculate resistance of bulb A is,

RA=V2PA

• RA is the resistance of bulb A,
• V is the voltage of power supply,
• PA is the power delivered to bulb A,

Substitute 120V for V and 25W for RA in the above equation to find RA .

RA=(120V)225W=576Ω                                                                            (I)

Therefore, the resistance of the light bulb A is 576Ω

(b)

To determine
The time taken by 1.00C charge to pass into light bulb A.

(c)

To determine
Whether the charge is different upon its exit versus entry into the light bulb.

(d)

To determine
The time interval for 1.00J pass into light bulb A.

(e)

To determine
Mechanisms with which energy enters and leaves the light bulb.

(f)

To determine
The cost of running light bulb A

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