A student weighs out 1.118g of impure HPT, dissolves the sample in deionized water and tirates it with 0.1001M of NaOH solution. If the titration requires 2710mL of the NaOH solution, and none of the impurities react with NaOH, what is the percent KHP in the sample? I'm confused why none of the impurities would react. I multipled 0.1001M by 2.71L and got 0.2172M of NaOH. As it's 1:1 ratio, shouldn't the point of equivalence be 0.2712 mol of KHP? But I do not have the volume of KHP so how can I calculate the molarity with only grams (which can be turned into mol) and no volume?

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions
Section4.9: Spectrophotometry
Problem 2.1ACP: Excess KI is added to a 100.0-mL sample of a soft drink that had been contaminated with bleach,...
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A student weighs out 1.118g of impure HPT, dissolves the sample in deionized water and tirates it with 0.1001M of NaOH solution. If the titration requires 2710mL of the NaOH solution, and none of the impurities react with NaOH, what is the percent KHP in the sample? I'm confused why none of the impurities would react. I multipled 0.1001M by 2.71L and got 0.2172M of NaOH. As it's 1:1 ratio, shouldn't the point of equivalence be 0.2712 mol of KHP? But I do not have the volume of KHP so how can I calculate the molarity with only grams (which can be turned into mol) and no volume? 

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