A target analyte A has a pk, value of 7.00 while the interferent B has a pKa value of 2.00. A mixture of A and B in water was extracted with diethyl ether. If A and B have almost the same value of distribution coefficient, which of the following will ensure higher extraction of A in the organic phase?
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- Please help The petition coeficiente between benzene and water for carta iLife is approximately 3.9 .you are given a 0.35 g sample of acetanilide dissolved in 100ml of water Which of the following extraction techniques will give q better recovery of.acetanilide from water A) one extraction with 60ml of benzene or b) two successive extractions with 30ml portions of benzene? Show calculation2. Describe and explain the effect(s) on your result for the following possible experimental errors. In each case, specify the component(s) whose percentage(s) would be too high or too low and explain your rationale why these would be changed. (a) After adding DCM to the counterfeit pharmaceutical at the beginning, you didn’t stir or shake the mixture before filtering. (b) Washing the sucrose recovered during the first vacuum filtration with water rather than DCM. (c) During the NaHCO3 extraction, you failed to mix the organic and aqueous layers thoroughly. (d) You mistakenly extracted the DCM solution with 5% HCl rather than 5% NaHCO3. (e) You neutralised the NaHCO3 solution to pH7 rather than pH2.Describe and explain the effect(s) on your result for the following possible experimental errors. In each case, specify the component(s) whose percentage(s) would be too high or too low and explain your rationale why these would be changed. (a) After adding DCM to the counterfeit pharmaceutical at the beginning, you didn’t stir or shake the mixture before filtering. (b) Washing the sucrose recovered during the first vacuum filtration with water rather than DCM. (c) During the NaHCO3 extraction, you failed to mix the organic and aqueous layers thoroughly. - B (d) You mistakenly extracted the DCM solution with 5% HCl rather than 5% NaHCO3. (e) You neutralised the NaHCO3 solution to pH7 rather than pH2.
- Following the monograph procedure, a 724-mg of aspirin (MW+180 g/mol) dissolved in 18.5 ml of cold neutralized alcohol. This solution was then initially titrated with 0.101 N sodium hydroxide solution, then later neutralized with 0.104 sulfuric acid. 1. What is the milliequivalent weight consumed by the acidic titrant? a. 1.5392 g-meq b. 2.0907 g-meq c. 1.4948 g-meq d. 2.1528 g-meq 2. What is the milliequivalent weight consumed by the basic titrant? a. 5.8656 g-meq b. 1.5392 g-meq c. 5.6964 g-meq d. 1.4948 g-meq 3. What is the difference of milliequivalent weight consumed in the reaction? a. -4.1572 g-meq b. 4.3708 g-meq c. 0.5515 g-meq d. 4.1572 g-meqIt has been noticed that adulteration of palm oil with carcinogenic dyes are on the rise. Use your knowledge in analytical processes to systematically process adultrated palm oil to gain qualitative and quantitative information spectroscopically about any added toxic.Explain also the basis for your protocol of choiceAny special precautions or purifications of the reagents required? Limiting and excess reagent? Why is excess necessary? 4,4'-DIBROMOBIPHENYL [Biphenyl, 4,4'-dibromo-] Submitted by Robert E. Buckles and Norris G. Wheeler1. Checked by R. S. Schreiber, Wm. Bradley Reid, Jr., and Robert W. Jackson. 1. Procedure In a 15-cm. evaporating dish is placed 15.4 g. (0.10 mole) of finely powdered biphenyl (Note 1). The dish is set on a porcelain rack in a 30-cm. desiccator with a 10-cm. evaporating dish under the rack containing 39 g. (12 ml., 0.24 mole) of bromine. The desiccator is closed, but a very small opening is provided for the escape of hydrogen bromide (Note 2). The biphenyl is left in contact with the bromine vapor for 8 hours (or overnight). The orange solid is then removed from the desiccator and allowed to stand in the air under a hood for at least 4 hours (Note 3). At this point, the product weighs about 30 g. and has a melting point in the neighborhood of 152°. The crude…
- Please provide a clear solution for me to study it. Thank you!Systematically outline a protocol you will follow to process adulterated palm oil to gain qualitative and quantitative information spectroscopically about any added toxic dye. Explain also the basis for your protocol of choice.outline a separation scheme for isolating pure aspirin. lab video: https://www.youtube.com/watch?v=Y4NMpO1xI8U
- 2. A sample of material contains for its active components NaOH, NazCO3, NaHCO3, or compatible mixtures of these. Two samples, each weighing 1.000 g, are dissolved in H20. To one sample phenolphthalein is added and the solution is titrated cold with 1.038 N acid, of which 17.96 mL is required. The other sample is titrated cold, with methyl orange as indicator, and 21.17 mL of the same acid is required. What alkalis are present, and what is the percentage of each in the original sample?Which of the following would be an optimal choice for a solvent extraction diluent and why? For the others, what limitations hold them back? a) Dodecane b) Methane c) Decanol d) Chloroform2c)Outline a method based on extraction techniques for the separation of a mixture of compound B from problem I., and compound A from problem II.