a The first four steps in the radioactive decay sequence of Bi-214 are a, B, B, a. To write the reaction equations for this decay series, first determine the product of the first step. a decay of Bi-214 gives: symbol = Po mass number = 214 atomic number = 84 b Bi undergoes four decay reactions: a, ß, B, a. Step 1. 33 Bi undergoes a decay to give 210 TI In the second step, TI-210 undergoes ß decay. What is the product of this step? symbol = mass number = atomic number = Submit

General, Organic, and Biological Chemistry
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Author:H. Stephen Stoker
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Chapter11: Nuclear Chemistry
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a The first four steps in the radioactive decay sequence of Bi-214 are a, B, B, a.
To write the reaction equations for this decay series, first determine the product of the first step.
a decay of Bi-214 gives:
symbol = Po
mass number = 214
atomic number = 84
b Bi undergoes four decay reactions: a, B, B, a.
Step 1.
214 Bi undergoes a decay to give 210 TI
83
In the second step, TI-210 undergoes B decay. What is the product of this step?
symbol =
mass number =
atomic number =
Submit
Transcribed Image Text:a The first four steps in the radioactive decay sequence of Bi-214 are a, B, B, a. To write the reaction equations for this decay series, first determine the product of the first step. a decay of Bi-214 gives: symbol = Po mass number = 214 atomic number = 84 b Bi undergoes four decay reactions: a, B, B, a. Step 1. 214 Bi undergoes a decay to give 210 TI 83 In the second step, TI-210 undergoes B decay. What is the product of this step? symbol = mass number = atomic number = Submit
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