A thin disk of radius R carries a uniformly distributed charge. The surface charge density on the disk is o. What is the electric field at a point P along the perpendicular axis through the disk center? O GETTING STARTED I begin with a sketch, placing the disk in the xy plane, with the disk center at the origin. I let point P lie on the positive z axis (Figure 23.29).

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Chapter6: Gauss's Law
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Example 23.6 Electric field created by a uniformly charged disk
A thin disk of radius R carries a uniformly distributed charge.
The surface charge density on the disk is o. What is the electric
field at a point P along the perpendicular axis through the disk
Figure 23.29
center?
O GETTING STARTED I begin with a sketch, placing the disk in
the xy plane, with the disk center at the origin. I let point P lie on
the positive z axis (Figure 23.29).
dr
2 DEVISE PLAN Because of the circular symmetry of the disk,
I divide it into a large number of ring-shaped segments, each of
radius r and width dr. The charge on each ring is the product of
the ring surface area (circumference times width) and the sur-
face charge density: dq, = (2Tr)dr o. The contribution of each
R
99+
QUANTITATIVE TOOLS
Transcribed Image Text:Example 23.6 Electric field created by a uniformly charged disk A thin disk of radius R carries a uniformly distributed charge. The surface charge density on the disk is o. What is the electric field at a point P along the perpendicular axis through the disk Figure 23.29 center? O GETTING STARTED I begin with a sketch, placing the disk in the xy plane, with the disk center at the origin. I let point P lie on the positive z axis (Figure 23.29). dr 2 DEVISE PLAN Because of the circular symmetry of the disk, I divide it into a large number of ring-shaped segments, each of radius r and width dr. The charge on each ring is the product of the ring surface area (circumference times width) and the sur- face charge density: dq, = (2Tr)dr o. The contribution of each R 99+ QUANTITATIVE TOOLS
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