A threaded screw specified by 1-in UNF will have: O d = 25 mm and p = 2 mm %3D O d = 1.0 in and N = 8 O d = 1.0 in and p = 12 mm %3D %3D O d = 1.0 in and N = 12
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- A cap screw, ¾ in.-10-UNC-2, with a hexagonal head that is 9/16 in. thick, carries a tensile load of 3000 lb. If the material is AISI 1015, cold drawn, find the factor of safety based on ultimate strengths of a. the threaded shank, b. the head against being sheared off, and c. the bearing surface under the head. d. Is there any need to consider the strength of standard cap-screw heads in design?A cap screw, ¾ in.-10-UNC-2, with a hexagonal head that is 9/16 in. thick, carries a tensile load of 3000 lb. If the material is AISI 1015, cold drawn, find the factor of safety based on ultimate strengths of a.the threaded shank, b.the head against being sheared off, and c.the bearing surface under the head. d.Is there any need to consider the strength of standard cap-screw heads in design?Design and draw a neat sketch of a cast iron protective type flange coupling to transmit “P” kW at “N” rpm. from a turbine generating n electric motor to a compressor. The service factor may be assumed as 1.35. The following permissible stress may be used: Shear stress for shaft, bolt and key material = 40 MPaCrushing stress for bolt and key = 80 MPaShear stress for cast iron = 8 Mpa Speed N in Rpm = 200Power P in kN = 16
- In the Bolted Connection shown, find the following by ASD.Specifications:M20 Bolts in standard holes. Nominal hole diameter = 22mmEffective Hole diameter = nominal hole diameter + 2 mmA325 steel boltAssume thread in shear planeFv = 372 MPaProperties of Angle Bar< 125 x 125 x 13 mmA = 3065 mm²x = 36.3 mmy = 36.3 mmFy = 248 MPa , Fu = 410 MPa 1. For angle bars used as bolted tension element connected to another element only on one leg, the effective area Ae = UAn. Where: An = Net area, U = Shear lag factor = 1 – x/L, L= center to center longitudinal distance of extremely located fasteners, X= distance from centroid of angle bar to surface of contact of joined elements. What is the shear lag factor of our angular bar? a. 0.454 b. 0.9 c. 0.838 d. 0.869 2. Considering RUPTURE of angle bar, what is the allowable force P that the connection can handle if allowable RUPTURE stress in net area of angle bar is Fu/2 a. 463.83 kN…For a square thread power screw, given that:F= 6.4 kNPitch = 5 mmMajor diameter = 32 mmTotal raising torque = 28 N.mThen then max. torsional shear stress equals:Draw FBD and determine Stress and Safety Factor of Bicycle Axle (Thru Axel) Specification Weight of cyclist = 120 kg. Materials: Aluminum alloy (AL 6061-T6) Dimension: Length = 122 mm, Diameter = 12 mm, Thread pitch = 1.75 mm, Thread Length = 16 mm.
- A flange coupling is to connect two 57 mm shafts. The hubs of the coupling are each 111 mm in diameter and 92mm thick and the flange web are 19 mm thick. Six 16 mm bolts in a 165 mm diameter circle connect the flange.The keyway is 6 mm shorter than the hub’s thickness and key is 14 mm x 14 mm. Coupling is to transmit 45 KW at160 rpm. For all parts, yield point value in shear is one – half the yield value which is 448 MPa. Calculate the forceon the shaftDesign and draw a neat sketch of a cast iron protective type flange coupling to transmit “P” kW at “N” rpm. from a turbine generating n electric motor to a compressor. The service factor may be assumed as 1.35. The following permissible stress may be used: Shear stress for shaft, bolt and key material = 40 MPaCrushing stress for bolt and key = 80 MPaShear stress for cast iron = 8 MpaSpeed N in Rpm = 500Power P in kN = 151. A jack having square threads of 50 mm nominal diameter and 10 mm pitch is supporting a load of 89 kN. A double thread is used and the coefficient of friction maybe as low as 0.10 or as high as 0.15.a. Will this screw always self-locking?b. What is the highest torque necessary to raise the load?
- A right angled bell crank lever is to be designed to raise a load of 5 kN at the short arm end. The lengths of short and long arms are 100 and 450 mm respectively. The lever and the pins are made of steel 30C8 (S = 400 N/mm2). And the factor of safety is 5.the permissible bearing pressure on the pin is 10 N/mm². The lever has a rectangular cross section and the ratio of width to thickness is 3:1. The length to diameter ratio of the fulcrum pin is 1.25:1. Calculate (i) The diameter and length of the fulcrum pin (ii) The dimensions of the cross section.A bushed pin type flexible coupling is used to transmit 10 kW power at 720 rpm. The design torque is 150% of rated torque. The keys have square cross-section. The permissible stresses are: For shaft and key material, τ = 66.67 N/mm2 , σc = 200 N/mm2 ; For pin material, τ = 35 N/mm2 , σt = 133 N/mm2 ; For flange material τ = 16.67 N/mm2 . The permissible bearing pressure for rubber bushes is 1 N/mm2. The number of bushes is 4. Design the bushed pin flexible coupling. Explain Axle, Spindle, Counter shaft and line-shaft with their examples .A bushed pin type flexible coupling is used to transmit 10 kW power at 720 rpm. The design torque is 150% of rated torque. The keys have square cross-section. The permissible stresses are: For shaft and key material, τ = 66.67 N/mm2, σc = 200 N/mm2; For pin material, τ = 35 N/mm2, σt = 133 N/mm2; For flange material τ = 16.67 N/mm2. The permissible bearing pressure for rubber bushes is 1 N/mm2. The number of bushes is 4. Design the bushed pin flexible coupling.