A toy submarine of mass m = 0.580 kg moves around a submerged circular track of radius R = 2.02 m. The submarine's engine provides a constant propulsion force of F = 5.13 N. When the sub is in motion, it is subject to a R. viscous drag force exerted by the water. This force is proportional to the sub's speed; the proportionality factor is C = 1.26 kg/s. Assuming it starts from rest at t = 0 s, the speed v(t) of the submarine at a later time t is given by F v (t) = (1 – e Culm) 000 where e is the base of the natural logarithm. 1600 How much time has passed when the submarine's speed reaches 64% of its terminal value? t = 0.4703 What is the magnitude of the submarine's acceleration a at this time? a = 3.184 m/s2 Incorrect
A toy submarine of mass m = 0.580 kg moves around a submerged circular track of radius R = 2.02 m. The submarine's engine provides a constant propulsion force of F = 5.13 N. When the sub is in motion, it is subject to a R. viscous drag force exerted by the water. This force is proportional to the sub's speed; the proportionality factor is C = 1.26 kg/s. Assuming it starts from rest at t = 0 s, the speed v(t) of the submarine at a later time t is given by F v (t) = (1 – e Culm) 000 where e is the base of the natural logarithm. 1600 How much time has passed when the submarine's speed reaches 64% of its terminal value? t = 0.4703 What is the magnitude of the submarine's acceleration a at this time? a = 3.184 m/s2 Incorrect
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter5: More Applications Of Newton’s Laws
Section: Chapter Questions
Problem 29P
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