Solve the following problems with complete solutions.A tugboat pulls a ship with a constant net horizontal force of 5.00 x 10 3 N and causes the ship to move through a harbor. How much work is done on the ship if it moves a distance of 3.00 km?Example is attached below. Please refer to it. Wtotal = (Frotal Cos 0)d = Frotald cos 0Еxample:How much work is done on a vacuum cleaner pulled 3.0 meter by a force of50.0 Newton at an angle of 30.0° above the horizontal?Given:F = 50.0 ND = 3.0 mØ = 30.0°W =?Using the equation:W = Fxd x cos ØW = (50.0 N) (3.0 m) (cos 30.0°)W = 130 J

Given data: Force (F) = 5×103 N Distance moved (d) = 3 km or x = 3×103 m we know that work done (W)…

Answered: A tugboat pulls a ship with a constant…

A tugboat pulls a ship with a constant net horizontal force of 5.00 x 10 3 N and causes the ship to move through a harbor. How much work is done on the ship if it moves a distance of 3.00 km?

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter9: Energy In Nonisolated Systems

Section: Chapter Questions

Problem 17PQ

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Question

Solve the following problems with complete solutions.

A tugboat pulls a ship with a constant net horizontal force of 5.00 x 10 3 N and causes the ship to move through a harbor. How much work is done on the ship if it moves a distance of 3.00 km?

Example is attached below. Please refer to it.

Wtotal = (Frotal Cos 0)d = Frotald cos 0
Еxample:
How much work is done on a vacuum cleaner pulled 3.0 meter by a force of
50.0 Newton at an angle of 30.0° above the horizontal?
Given:
F = 50.0 N
D = 3.0 m
Ø = 30.0°
W =?
Using the equation:
W = Fxd x cos Ø
W = (50.0 N) (3.0 m) (cos 30.0°)
W = 130 J

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