A two-liter sample of mineral water was evaporated to a small volume, following which the potassium ion was precipitated with excess sodium tetraphenylboron: K*1 + NaB(C.Hs)4 → KB(CHs)4 19) The precipitate was filtered, washed and redissolved in acetone. The analysis was completed by a Mohr titration that required 43.85-mL of 0.03941M AGNO3: KB(C,Hs)4 (5) + Ag → AgB(CaHs)a ce) + K** Calculate the potassium ion concentration (parts per million) of the water sample. Molar Mass: K = 39.10
A two-liter sample of mineral water was evaporated to a small volume, following which the potassium ion was precipitated with excess sodium tetraphenylboron: K*1 + NaB(C.Hs)4 → KB(CHs)4 19) The precipitate was filtered, washed and redissolved in acetone. The analysis was completed by a Mohr titration that required 43.85-mL of 0.03941M AGNO3: KB(C,Hs)4 (5) + Ag → AgB(CaHs)a ce) + K** Calculate the potassium ion concentration (parts per million) of the water sample. Molar Mass: K = 39.10
Chapter17: Complexation And Precipitation Reactions And Titrations
Section: Chapter Questions
Problem 17.35QAP
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Answer provided: 33.8-ppm K^+1
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Transcribed Image Text:A two-liter sample of mineral water was evaporated to a small volume, following which the potassium
ion was precipitated with excess sodium tetraphenylboron:
Ki + NaB(CHs))4 → KB(C&Hs)4 15)
The precipitate was filtered, washed and redissolved in acetone. The analysis was completed by a
Mohr titration that required 43.85-mL of 0.03941M AGNO3:
KB(C,Hs)4 (5) + Ag → AgB(C&Hs)4 (e) + K**
Calculate the potassium ion concentration (parts per million) of the water sample.
Molar Mass:
K = 39.10
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