(а) у — 2х %3D2 y + 2x = - 1 (b) у - 2х 3 0 2y + x = 0 (c) 2y – x = 2 2y + x = -2 (d) у - 2х 3D 2 x + 2y = -1 (e) 2x + y = -2 2y +x = -2

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter11: Systems Of Equations
Section11.5: Cramer's Rule
Problem 3CQ
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The figure shows the graph of two perpendicular lines.
Which of the following pairs of equations might have such a
graph

(а) у — 2х %3D2
y + 2x = - 1
(b) у - 2х 3 0
2y + x = 0
(c) 2y – x = 2
2y + x = -2
(d) у - 2х 3D 2
x + 2y = -1
(e) 2x + y = -2
2y +x = -2
Transcribed Image Text:(а) у — 2х %3D2 y + 2x = - 1 (b) у - 2х 3 0 2y + x = 0 (c) 2y – x = 2 2y + x = -2 (d) у - 2х 3D 2 x + 2y = -1 (e) 2x + y = -2 2y +x = -2
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